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Use the table or technology to find the answer to each question. Include an appropriately labeled sketch of the Normal curve for each part. Shade the appropriate region. A section of the Normal table is provided. a. Find the area in a Standard Normal curve to the left of \(1.13 .\) b. Find the area in a Standard Normal curve to the right of \(1.13 .\)

Short Answer

Expert verified
The area to the left of \(1.13\) in a Standard Normal curve is approximately \(87.08\%\) (0.8708) and to the right of \(1.13\) is approximately \(12.92\%\) (0.1292).

Step by step solution

01

Understanding the Standard Normal Distribution

The Standard Normal Distribution is a special type of normal distribution with a mean of 0 and a standard deviation of 1. The z-score is a measure of how many standard deviations an element is from the mean.
02

Finding the Area to the Left of the Z-Score (a)

A z-score of \(1.13\) will be utilized. The area to the left of this value is found by consulting the standard normal table. The corresponding probability for Z = \(1.13\) is \(0.8708\) or \(87.08\% \) which represents the area to the left of this z-score.
03

Sketching the Standard Normal Curve for (a)

The standard normal curve is symmetric around a mean of 0. Perform a sketch of the normal distribution, then shade the area to the left of 1.13 to visualize the solution.
04

Finding the Area to the Right of the Z-Score (b)

Again, a z-score of \(1.13\) is used. However, this time, the area to the right of this value is required. As it is known that the total area under the curve is 1 or \(100\% \), subtract the found left area from this total. So, the area to the right of \(1.13\) is \(1 - 0.8708 = 0.1292 \) or \(12.92\% .\)
05

Sketching the Standard Normal Curve for (b)

Draw another normal distribution graph for this part of the problem. But this time, shade the area to the right of 1.13 to indicate the solution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Z-Score
The z-score is a crucial concept within the realm of the standard normal distribution. It essentially measures how far away a specific data point is from the average, which in the case of the standard normal distribution, is 0. This distance is expressed in terms of standard deviations. If you have a z-score of, say, 1.13, it means that the data point is 1.13 standard deviations above the mean.

The formula to calculate the z-score is: \[ z = \frac{X - \mu}{\sigma} \]where
  • \(X\) is the value for which you are calculating the z-score.
  • \(\mu\) is the mean of the distribution.
  • \(\sigma\) is the standard deviation of the distribution.
Z-scores are very handy as they allow us to compare data from different normal distributions and determine their position within a distribution.

In a practical scenario, you would use z-scores to determine probabilities and understand how likely a data point is to occur under a normal distribution. As you translate this standard deviation count into a probability, you need to turn to the normal distribution table.
Using the Normal Distribution Table
The normal distribution table, often referred to as the z-table, is a valuable tool for anyone working with statistics. It provides the probabilities or areas associated with z-scores, which represent values under the standard normal distribution curve.

This table only shows one side of the curve. Normally, it provides the area to the left of a specified z-score. To find the probability of a z-score less than or equal to 1.13, you simply look up 1.13 in the table. For instance, in this case, the table tells us that approximately 87.08% of the data falls to the left of a z-score of 1.13.

When you need to find the area to the right of a particular z-score, you subtract the left-side area from 1, since the entire area under the curve sums to 1 or 100%. So for a z-score of 1.13, you calculate the right-side area as follows:\[1 - 0.8708 = 0.1292 \]
This calculation indicates that 12.92% of the data lies to the right of the z-score.

Using the table, in combination with sketches of the normal curve, helps to provide a visual understanding of where data lies in terms of probability and distribution.
Exploring Probability in Statistics
Probability in statistics allows us to predict the likelihood of an event or outcome. In many situations, such as when working with normal distributions, probability helps determine how often you can expect a certain event to occur.

For example, if you roll a die, each side has a 1 in 6, or about 16.67% probability of being rolled. When dealing with continuous data and distributions, such as the normal distribution, the concept of probability becomes more nuanced and mathematical tools like the z-score and normal distribution table are utilized.

In the normal distribution scenario, each data point has a specific probability tied to it, as estimated by its position on the curve. The closer it is to the mean, the more probable it is according to the bell curve's shape. Utilizing z-scores, you can precisely ascertain this probability.

Understanding these probabilities provides insights into the likelihood of certain observations, helping to make informed decisions based on statistical data. As such, comprehending how probability works in tandem with the standard normal distribution can aid significantly in interpreting data accurately.

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Most popular questions from this chapter

The distribution of red blood cell counts is different for men and women. For both, the distribution is approximately Normal. For men, the middle \(95 \%\) range from \(4.5\) to \(5.7\) million cells per microliter and for women, the middle \(95 \%\) have red blood cells counts between \(3.9\) and \(5.0\) million cells per microliter. a. What is the mean and the standard deviation of red blood cell counts for men? Explain your reasoning. b. What is the mean and the standard deviation of red blood cell counts for women? Explain your reasoning. c. Which gender shows more variation in red blood cell counts? Support your answer with appropriate statistics.

Extreme Positive z-Scores For each question, find the area to the right of the given \(z\) -score in a standard Normal distribution. In this question, round your answers to the nearest \(0.000\). Include an appropriately labeled sketch of the \(N(0,1)\) curve. a. \(z=4.00\) b. \(z=10.00\) (Hint: Should this tail proportion be larger or smaller than the answer to part a? Draw a picture and think about it.) c. \(z=50.00\) d. If you had the exact probability for these tail proportions, which would be the largest and which would be the smallest? e. Which is equal to the area in part b: the area below (to the left of) \(z=-10.00\) or the area above (to the right of) \(z=-10.00\) ?

According to dogtime .com, the mean weight of an adult St. Bernard dog is 150 pounds. Assume the distribution of weights is Normal with a standard deviation of 10 pounds. a. Find the standard score associated with a weight of 170 pounds. b. Using the Empirical Rule and your answer to part a, what is the probability that a randomly selected St. Bernard weighs more than 170 pounds? c. Use technology to confirm your answer to part \(\mathrm{b}\) is correct. d. Almost all adult St. Bernard's will have weights between what two values?

Suppose college women's heights are approximately Normally distributed with a mean of 65 inches and a population standard deviation of \(2.5\) inches. What height is at the 20th percentile? Include an appropriately labeled sketch of the Normal curve to support your answer.

Assume college women's heights are approximately Normally distributed with a mean of 65 inches and a standard deviation of \(2.5\) inches. Choose the StatCrunch output for finding the percentage of college women who are taller than 67 inches and report the correct percentage. Round to one decimal place.

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