/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 Use the table or technology to f... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Use the table or technology to find the answer to each question. Include an appropriately labeled sketch of the Normal curve for each part. Shade the appropriate region. A section of the Normal table is provided in the previous exercise. a. Find the area to the left of a \(z\) -score of \(0.92\). b. Find the area to the right of a z-score of \(0.92\).

Short Answer

Expert verified
The area to the left of the z-score 0.92 is 0.8212, and the area to the right is 0.1788

Step by step solution

01

Understand Normal Distribution and Z-scores

Z-scores represent how many standard deviations an element is from the mean. In a standard normal distribution, mean (μ) is 0 and standard deviation (σ) is 1. It is symmetric and follows the empirical rule.
02

Find the area to the left of a z-score of 0.92

Using the standard normal distribution table or z-table, find the area left of the z-score. The z-table gives the area to the left of a given z-value. For a z-value of 0.92, the table provides the PageRank as 0.8212. This represents the area to the left of the z-score of 0.92. Therefore, \(P(Z < 0.92) = 0.8212.\)
03

Find the area to the right of a z-score of 0.92

The total area under a standard normal distribution curve is 1. The area to the right of a z-score is found by subtracting the area to the left of that z-score from 1, since the total probability is 1. Hence, \(P(Z > 0.92) = 1 - P(Z < 0.92) = 1 - 0.8212 = 0.1788.\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
Understanding the concept of Normal distribution is pivotal in statistics since it serves as the foundation for various statistical analyses. It is a continuous probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean. Imagine ringing the bell at a carnival game; the highest point of the bell represents the mean where most of the results cluster, while the sides represent the extreme values occurring less frequently.

In a Normal distribution, the mean, median, and mode are all located at the highest point of the curve, and its shape reflects the distribution of values around this central point. The distribution is often referred to as a 'bell curve' due to its bell-like shape. It's important to know that the area under the curve represents the total probability and is equal to 1. When dealing with any set of data, calculating the z-score of an observation can help identify its position within the distribution.
Standard Normal Distribution Table
A Standard normal distribution table, also known as a z-table, is a handy tool for understanding where a particular score falls within a normal distribution. This table is used to find the probability of a z-score (or a range of z-scores) falling to the left of a certain point on the standard normal curve. The z-table lists z-scores in one axis and corresponding probabilities in the other.

Interpreting a Z-table

To use a z-table, locate the z-score of interest and find its corresponding probability in the table. This probability reflects the area under the curve to the left of the z-score. The central idea here is that each score tells us about the relative position of a value within the distribution. When calculations require the area to the right, simply subtract the left area from the total probability of 1, as seen in the solution to the provided exercise. It is essential to be familiar with reading such tables accurately, as they are often used to determine areas without relying on computational technology.
Area Under the Curve
The concept of 'area under the curve' in the context of a normal distribution graph represents the probability of a data value falling between two points (or to one side of a point) on the distribution. For a standard normal distribution, the total area under the curve is 1, which corresponds to a 100% probability that a score chosen at random will fall somewhere under the curve.

This area can be divided into segments each representing the likelihood of a variable falling within a particular range. For instance, the area to the left of a z-score provides the probability of a variable being less than that z-score. Similarly, the area to the right would represent the probability of the variable being greater. For the exercise provided, shading the correct region on the curve and referring to a z-table made it possible to visualize and calculate the specific areas representing these probabilities, thus enhancing understanding of the normal distribution's application to real-world scenarios.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In a standard Normal distribution, if the area to the left of a z-score is about \(0.6666\), what is the approximate z-score? First locate, inside the table, the number closest to \(0.6666 .\) Then find the z-score by adding \(0.4\) and \(0.03\); refer to the table. Draw a sketch of the Normal curve, showing the area and the \(z\) -score.

A married couple plans to have four children, and they are wondering how many boys they should expect to have. Assume none of the children will be twins or other multiple births. Also assume the probability that a child will be a boy is \(0.50 .\) Explain why this is a binomial experiment. Check all four required conditions.

Weather New York City's mean minimum daily temperature in February is \(27^{\circ} \mathrm{F}\) (http://www.ny.com). Suppose the standard deviation of the minimum temperature is \(6^{\circ} \mathrm{F}\) and the distribution of minimum temperatures in February is approximately Normal. What percentage of days in February has minimum temperatures below freezing \(\left(32^{\circ} \mathrm{F}\right)\) ?

Survey data, the distribution of arm spans for males is approximately Normal with a mean of \(71.4\) inches and a standard deviation of \(3.3\) inches. a. What percentage of men have arm spans between 66 and 76 inches? b. Professional basketball player, Kevin Durant, has an arm span of almost 89 inches. Find the \(z\) -score for Durant's arm span. What percentage of males have an arm span at least as long as Durant's?

Toss a fair six-sided die. The probability density function (pdf) in table form is given. Make a graph of the pdf for the die. $$\begin{array}{lcccccc}\text { Number of Spots } & 1 & 2 & 3 & 4 & 5 & 6 \\\\\hline \text { Probability } & 1 / 6 & 1 / 6 & 1 / 6 & 1 / 6 & 1 / 6 & 1 / 6\end{array}$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.