/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 43 In a standard Normal distributio... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In a standard Normal distribution, if the area to the left of a z-score is about \(0.6666\), what is the approximate z-score? First locate, inside the table, the number closest to \(0.6666 .\) Then find the z-score by adding \(0.4\) and \(0.03\); refer to the table. Draw a sketch of the Normal curve, showing the area and the \(z\) -score.

Short Answer

Expert verified
The approximate z-score for an area of \(0.6666\) on the left side is \(0.43\).

Step by step solution

01

Locate the Value in the Z-table

Start by looking up the value closest to \(0.6666\) in the z-table. This provides the cumulative probability of a standard normal random variable. Note: The z-table value should give a number as close as possible to \(0.6666\) if the exact value does not exist.
02

Identify the Z-score

To identify the z-score for a given percentile, we need to reverse lookup the percentile in the standard normal (z) table. In this case, based on the instructions, we add \(0.4\) and \(0.03\) to find the z-score, which makes the z-score equal to \(0.43\). This indicates that approximately 66.66% (or 0.6666) of the data falls below a z-score of \(0.43\).
03

Draw the Normal Curve

Sketch the Normal curve. The horizontal axis represents the z-scores, the center indicates the mean value which is \(0\) in a standard Normal distribution. Mark the z-score \(0.43\) on the horizontal line, representing the score below which approximately 66.66% of the data falls. Shade the area to the left of this z-score to indicate the proportional area of about \(0.6666\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-score
When working with a set of data, one of the ways to tell how an individual data point compares to the average is by using a z-score. The z-score is a numerical measurement that describes a value's relationship to the mean of a group of values, measured in terms of standard deviations from the mean. If a z-score is 0, it is at the mean. A positive z-score indicates the value is above the mean and a negative score says it's below. For example, if the area to the left of a z-score is approximately 0.6666, we're lookng at a point that's higher than 66.66% of all data points in the normal distribution.

To calculate a z-score you'd use the formula:
\[\[\begin{align*}\( z = \frac{{X - \mu}}{{\sigma}} \)\end{align*}\]\]
Here, \(X\) is the value you are interested in, \(\mu\) is the mean of the dataset, and \(\sigma\) is the standard deviation. This calculation will yield a score which helps in understanding where the value stands in comparison to the rest of the data set.
Normal curve
The Normal curve, also known as the Gaussian curve or bell curve, represents the standard normal distribution graphically. It's symmetric around its mean and has a single peak right at the center, where the mean, median, and mode of the distribution are all equal. The spread of a Normal curve is determined by its standard deviation, which dictates how dispersed the values are around the mean.

Standard normal distribution specifically has a mean of 0 and a standard deviation of 1. The percentage of data within certain ranges can be determined through the properties of the Normal curve. For example, about 68% of the data falls within one standard deviation, 95% within two standard deviations, and 99.7% within three standard deviations of the mean.

In the context of the provided exercise, the Normal curve helps visualize how much of the data falls below the z-score of approximately 0.43.
Cumulative probability
The concept of cumulative probability is tied to the Normal curve and z-scores. It refers to the probability that a variable will take a value less than or equal to a certain number. In the standard normal distribution, it is the area under the curve to the left of a specific z-score.

For instance, a cumulative probability of 0.6666 means that there is a 66.66% chance that a randomly selected score from the distribution is less than or equal to the associated z-score. Cumulative probability is fundamental when addressing the question of 'how much of all possible outcomes fall below a specific threshold?' and is practically depicted as the area under the normal curve to the left of a z-score point.
Reverse lookup in z-table
Sometimes, you know the cumulative probability (the area under the Normal curve to the left of the z-score) but need to find the corresponding z-score. This process is known as a reverse lookup in z-table. A z-table, or standard normal table, shows the cumulative probability for z-scores along the Normal curve.

To perform a reverse lookup, you start with the cumulative probability and search the table for the closest value, then locate the corresponding z-score. This z-score is the number of standard deviations away from the mean. In the exercise at hand, to find a z-score that corresponds to a cumulative probability of 0.6666, you would look through the z-table, locate the area closest to that value, and then determine the z-score that aligns with it. Adding up the values as the exercise suggests (0.4 and 0.03), you arrive at the z-score (0.43) connected to the 66.66% cumulative probability.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

According to the American Veterinary Medical Association, \(36 \%\) of Americans own a dog. a. Find the probability that exactly 4 out of 10 randomly selected Americans own a dog. b. In a random sample of 10 Americans, find the probability that 4 or fewer own a dog.

Alaska Airlines has an on-time arrival rate of \(88 \%\). Assume that in one day, this airline has 1200 flights. Suppose we pick one day in December and find the number of ontime Alaska Airline arrivals. Why would it be inappropriate to use the binomial model to find the probability that at least 1100 of the 1200 flights arrive on time? What condition or conditions for use of the binomial model is or are not met?

The use of drones, aircraft without onboard human pilots, is becoming more prevalent in the United States. According to a 2017 Pew Research Center report, \(59 \%\) of American had seen a drone in action. Suppose 50 Americans are randomly selected. a. What is the probability that at least 25 had seen a drone? b. What is the probability that more than 30 had seen a drone? c. What is the probability that between 30 and 35 had seen a drone? d. What is the probability that more than 30 had not seen a drone?

A study of U.S. births published on the website Medscape from WebMD reported that the average birth length of babies was \(20.5\) inches and the standard deviation was about \(0.90\) inch. Assume the distribution is approximately Normal. Find the percentage of babies with birth lengths of 22 inches or less.

According to the National Health Center, the heights of 5 -year-old boys are Normally distributed with a mean of 43 inches and a standard deviation of \(1.5\) inches. a. In which percentile is a 5 -year-old boy who is \(46.5\) inches tall? b. If a 5 -year-old boy who is \(46.5\) inches tall grows up to be a man at the same percentile of height, what height will he be? Assume adult men's heights (inches) are distributed as \(N(69,3)\).

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.