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According to the American Veterinary Medical Association, \(36 \%\) of Americans own a dog. a. Find the probability that exactly 4 out of 10 randomly selected Americans own a dog. b. In a random sample of 10 Americans, find the probability that 4 or fewer own a dog.

Short Answer

Expert verified
a. The probability that exactly 4 out of 10 randomly selected Americans own a dog is approximately 0.159. b. The probability that 4 or fewer Americans in a random sample of 10 own a dog is approximately 0.403.

Step by step solution

01

Understanding and Applying Binomial Probability

Given the probability of owning a dog \( p = 0.36 \) (36% expressed as a decimal) and the number of trials \( n = 10 \). For a binomial distribution, the probability of exactly \( k \) successes out of \( n \) trials is given by the formula:\[ P(x=k) = C(n, k) * (p^k) * ((1-p)^(n-k)) \]where C(n, k) is the binomial coefficient, which can be calculated as \[ C(n, k) = n! / [(n-k)! * k!] \]Now, plug the given values in the above formula to find the probability that exactly 4 out of 10 randomly selected Americans own a dog.
02

Calculations for Part (a)

First, calculate the binomial coefficient \( C(10, 4) = 210 \). Then calculate the success term \( (0.36^4) = 0.0168 \) and the failure term \( ((1-0.36)^{10-4}) = 0.021 \). Finally, multiply all these terms to find the binomial probability \(P(x=4) = 210 * 0.0168 * 0.021 \).
03

Understanding and Applying Cumulative Binomial Probability

In part b, the problem specifies finding the probability that '4 or fewer' Americans own a dog. This means we need to find the cumulative binomial probability from x=0 up to x=4. This is done by summing up the probabilities calculated from the binomial probability formula for x=0 to x=4.
04

Calculations for Part (b)

Calculate the cumulative binomial probabilities \(P(x=0), P(x=1), P(x=2), P(x=3)\), and \(P(x=4)\) using the binomial probability formula. Then, sum up these probabilities.

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