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Standard Normal Use technology or a Normal table to find each of the following. Include an appropriately labeled sketch of the Normal curve for each part with the appropriate area shaded. a. Find the probability that a \(z\) -score will be \(2.12\) or greater. b. Find the probability that a \(z\) -score will be less than \(-0.74\). c. Find the probability that a \(z\) -score will between \(1.25\) and \(2.37\).

Short Answer

Expert verified
The probabilities are calculated per technology or the standard table for normal distribution. The area under the corresponding parts of the curve is shaded.

Step by step solution

01

Part (a) - Calculate the probability for Z > 2.12

Find the probability for \(Z \leq 2.12\) from the standard normal distribution table. Let's say it is \(A\). The probability that a Z-score is greater than \(2.12\) can be found by subtracting this probability from \(1\) since the total probability under the curve is \(1\). The result is \(1 - A\). Shade the area under the curve to the right of \(2.12\)
02

Part (b) - Calculate the probability for Z < -0.74

Find the probability for \(Z \leq -0.74\) directly from the standard normal distribution table. This is the probability that a Z score is less than \(-0.74\). Let's denote it as \(B\). Shade the corresponding left tail area under the curve.
03

Part (c) - Calculate the probability for 1.25 < Z < 2.37

To find the probability that a Z-score is between \(1.25\) and \(2.37\), we need to calculate the probabilities for \(Z \leq 2.37\) and \(Z \leq 1.25\) from the standard normal distribution table and subtract the latter from the former. Let's denote them as \(C\) and \(D\) respectively. The result is \(C - D\). The area to be shaded is between \(1.25\) and \(2.37\) under the curve.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-Score Probability
When we refer to a z-score probability, we're talking about the probability of a random variable falling within a certain area of the standard normal distribution. The z-score itself is a statistical measure that describes a value's relation to the mean of a group of values, standardized to units of standard deviation. So, a z-score of 2.12 means the observed value is 2.12 standard deviations above the mean.

Calculating the probability associated with a particular z-score typically involves using a standard normal distribution table. This table lists the probabilities that a standard normal variable will take on a value to the left of a given z-score. For instance, to solve for the probability that a z-score will be 2.12 or greater, one would look up the probability for a z-score of 2.12 (let's call this probability A) and subtract it from 1, since the total area under the curve represents 100% probability. The chance that a z-score will be greater than 2.12 is then given by the complement, making it 1 - A.
Normal Distribution Table
The normal distribution table, also known as the z-table, is an indispensable tool for working with the standard normal distribution. It's usually formatted such that the table entries represent the area to the left of the z-score. To use the table, you find your given z-score along the margins, and the corresponding value inside the table will be the cumulative probability.

For example, if a student needs to find the probability for a z-score less than -0.74 (as stated in part b of our exercise), they would locate -0.74 in the z-table, and use the corresponding value, let's call it B, as the probability. This B value represents the area to the left of the -0.74 z-score. Understanding how to read and interpret this table is crucial for accurately calculating probabilities and areas under the normal curve.
Shading Normal Curve Areas
In the context of normal distributions, shading areas under the curve is a visual method used to represent probabilities. Each shaded region corresponds to a range of values and their associated probability. In standard normal distribution exercises, the shaded area can illustrate probabilities to the left, right, or between certain z-scores.

For example, in part c of our exercise, we need to find the shaded area between z-scores 1.25 and 2.37. By finding the cumulative probabilities corresponding to these z-scores (C and D, respectively), we can shade the area on a graph between these two points to represent all values that fall within this z-score range. The probability that a z-score is between 1.25 and 2.37 is then found by calculating the area of this shaded region, which is the difference between these two probabilities, or C - D. Such visual aids are beneficial for students to understand the concepts of probability and distribution in a more tangible manner.

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Most popular questions from this chapter

Use the table or technology to find the answer to each question. Include an appropriately labeled sketch of the Normal curve for each part. Shade the appropriate region. A section of the Normal table is provided in the previous exercise. a. Find the area to the left of a \(z\) -score of \(0.92\). b. Find the area to the right of a z-score of \(0.92\).

Assume that the lengths of pregnancy for humans is approximately Normally distributed, with a mean of 267 days and a standard deviation of 10 days. Use the Empirical Rule to answer the following questions. Do not use the technology or the Normal table. Begin by labeling the horizontal axis of the graph with lengths, using the given mean and standard deviation. Three of the entries are done for you. a. Roughly what percentage of pregnancies last more than 267 days? i. almost all iii. \(68 \%\) ii. \(95 \%\) iv. \(50 \%\) b. Roughly what percentage of pregnancies last between 267 and 277 days? i. \(34 \%\) iii. \(2.5 \%\) ii. \(17 \%\) iv. \(50 \%\) c. Roughly what percentage of pregnancies last less than 237 days? i. almost all iii. \(34 \%\) ii. \(50 \%\) iv. about \(0 \%\) d. Roughly what percentage of pregnancies last between 247 and 287 days? i. almost all iii. \(68 \%\) ii. \(95 \%\) iv. \(50 \%\) e. Roughly what percentage of pregnancies last longer than 287 days? i. \(34 \%\) iii. \(2.5 \%\) ii. \(17 \%\) iv. \(50 \%\) f. Roughly what percentage of pregnancies last longer than 297 days? i. almost all iii. \(34 \%\) ii. \(50 \%\) iv. about \(0 \%\)

Use technology or a Normal table to find each of the following. Include an appropriately labeled sketch of the Normal curve for each part with the appropriate area shaded. a. Find the probability that a \(z\) -score will be \(2.03\) or less. b. Find the probability that a \(z\) -score will be \(-1.75\) or more. c. Find the probability that a \(z\) -score will be between \(-1.25\) and \(1.40\).

Quantitative S \(\Lambda\) T scores are approximately Normally distributed with a mean of 500 and a standard deviation of 100 . Choose the correct StatCrunch output for finding the probability that a randomly selected person scores less than 450 on the quantitative SAT and report the probability as a percentage rounded to one decimal place.

In a standard Normal distribution, if the area to the left of a \(z\) -score is about \(0.1000\), what is the approximate \(z\) -score?

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