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Suppose there is a club for tall people that requires that women be at or above the 98 th percentile in height. Assume that women's heights are distributed as \(N(64,2.5)\). Find what women's height is the minimum required for joining the club, rounding to the nearest inch. Draw a well-labeled sketch to support your answer.

Short Answer

Expert verified
The minimum height requirement for the club is 69 inches.

Step by step solution

01

Understand the task

The club accepts women who are in the 98th percentile or higher of all women. In other words, their height needs to be greater than or equal to the height of 98% of all women. Since women's heights are normally distributed, we will use the properties of the normal distribution to solve this.
02

Use the Z-Score table

To find the height corresponding to the 98th percentile, we need to find the z-score that corresponds to a cumulative probability of 0.98 using a Z-table or a calculator with a normal distribution function. Looking this up in a standard Z-table or using an appropriate calculator function reveals that 98% cumulative probability corresponds to a z-score of roughly 2.05.
03

Find the height

The z-score formula is \(Z = (X - \mu) / \sigma\), where X is the value from our data set, \(\mu\) is the mean and \(\sigma\) is the standard deviation. We need to solve for X since we want to find the corresponding height: \(X = Z \cdot \sigma + \mu = 2.05 \cdot 2.5 + 64\). Calculating this gives us X ≈ 69.125.
04

Round the result

The exercise wants the answer rounded to the nearest inch. Therefore, X = 69 inches, which means that 69 inches is the minimum height requirement for women to join the club.
05

Sketch a normal distribution graph

Draw a standard bell curve, mark the mean (64) in the center. Standard deviations are marked on the x-axis, here 2.5 units apart. Draw a vertical line through the point that represents the 98th percentile (69). Every height to the right of this point is in the top 2% of all women's heights, so women with these heights are eligible to join the club.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normal Distribution
The concept of normal distribution is fundamental in statistics and forms the basis of many statistical analyses. It is commonly represented by a bell-shaped curve that is symmetrical about the mean. For a set of data that follows the normal distribution, the mean, median, and mode are all equal and located at the center of the distribution. The curve's spread is determined by the standard deviation, which measures how much the individual data points deviate from the mean.

When a data set has a normal distribution, as is the case with the women's heights in the exercise, approximately 68% of the data falls within one standard deviation of the mean, 95% falls within two standard deviations, and 99.7% falls within three standard deviations. In the given exercise, the tall club is interested in the height threshold for the top 2% of women, which is to say the 98th percentile. This value lies well beyond two standard deviations from the mean on the right side of the distribution curve.
Z-score
A Z-score is a statistical measure that describes a value's relationship to the mean of a group of values, measured in terms of standard deviations from the mean. This score is used to determine how unusual a value is compared to all the values in the data set.

To calculate a Z-score, you subtract the mean from the value in question and then divide the result by the standard deviation of the group. The formula looks like this: \(Z = \frac{X - \mu}{\sigma}\), where \(X\) is the value, \(\mu\) is the mean, and \(\sigma\) is the standard deviation. In the exercise, the Z-score is used to identify the 98th percentile: it is the number of standard deviations the 98th percentile height is above the average height for women. A positive Z-score indicates a value above the mean, while a negative Z-score indicates a value below the mean. The 98th percentile corresponds to a Z-score of approximately 2.05, meaning that height is a little over two standard deviations above the mean.
Cumulative Probability
Cumulative probability in statistics refers to the likelihood that a random variable takes on a value less than or equal to a specified value. In the context of the normal distribution, cumulative probability is represented by the area under the distribution curve to the left of a given point. This area corresponds to the probability that a value is below a certain threshold and is of chief importance when dealing with percentiles.

For example, to find the 98th percentile in the exercise, we use cumulative probability to determine the smallest height such that 98% of women are at or below that height. The cumulative probability associated with the 98th percentile is 0.98, meaning 98% of the distribution falls below this point. This value is what we look up in the Z-table or calculate using a statistical software to find the matching Z-score. The cumulative probability connects the percentile rank to its equivalent Z-score, thereby enabling us to calculate the corresponding value (the height) in the specific distribution being studied.

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Most popular questions from this chapter

Use a table or technology to answer each question. Include an appropriately labeled sketch of the Normal curve for each part. Shade the appropriate region. a. Find the probability that a \(z\) -score will be \(-1.00\) or less. b. Find the probability that a \(z\) -score will be more than \(-1.00\). c. Find the probability that a \(z\) -score will be between \(0.90\) and \(1.80\).

According to the National Health Center, the heights of 5 -year-old boys are Normally distributed with a mean of 43 inches and standard deviation of \(1.5\) inches. a. In which percentile is a 5 -year-old boy who is \(46.5\) inches tall? b. If a 5 -year-old boy who is \(46.5\) inches tall grows up to be a man at the same percentile of height, what height will he be? Assume adult men's heights (inches) are distributed as \(N(69,3)\).

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A fair die is rolled 60 times. a. What is the expected number of times that an odd number will turn up? b. Find the standard deviation for the outcome to be an odd number. c. How many times should you expect odd numbers to turn up, give or take how many times? Based on these numbers, give the range of the number of times odd numbers can turn up.

A married couple plans to have four children, and they are wondering how many boys they should expect to have. Assume none of the children will be twins or other multiple births. Also assume the probability that a child will be a boy is \(0.50 .\) Explain why this is a binomial experiment. Check all four required conditions.

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