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College women have a mean height of 65 inches and a standard deviation of \(2.5\) inches. The distribution of heights for this group is Normal. Choose the correct StatCrunch output for finding the percentage of college women with heights of less than 63 inches, and report the correct percentage.

Short Answer

Expert verified
The percentage of college women with heights less than 63 inches, calculated based on the given mean and standard deviation, is approximately 21.19%.

Step by step solution

01

Calculating the Z-score

First we need to calculate the z-score which is a measure of how many standard deviations an element is from the mean. This can be calculated using the formula \( z = (X - μ) / σ \), where X is the value from the data set (in this case, the 63 inches), μ is the mean (in this case, the 65 inches) and σ is the standard deviation (in this case, the 2.5 inches). If we substitute, we obtain \( z = (63 - 65) / 2.5 = -0.8 \)
02

Finding the associated percentage

Once we have the z-score, we can use a standard normal distribution table or statistical software to find the percentage of data below this score. If using a table, we want to find the value associated with -0.8. If using software like StatCrunch, we perform a less than z-test and enter our z-score, -0.8. This tells us the percentage of college women with heights of less than 63 inches.
03

Interpreting the result

The result you obtain from the previous step is the percentage of college women with heights of less than 63 inches. Remember that the percentage or probability in statistics is often expressed as a decimal. So if the value you got was 0.2119, that would mean 21.19%. This is the final result, the percentage of college women with heights of less than 63 inches in a normal distribution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Z-score Calculation
Understanding the Z-score is essential for analyzing where a particular score lies within a normal distribution. Simply put, a Z-score represents the number of standard deviations an observation is above or below the mean. To calculate it, use the formula:
\[ z = \frac{(X - \text{μ})}{\text{σ}} \]
where \( X \) is the value of interest, \( \text{μ} \) is the mean, and \( \text{σ} \) is the standard deviation. For instance, if we have a group of college women whose mean height is 65 inches with a standard deviation of 2.5 inches, and we want to calculate the Z-score for a height of 63 inches, it would be:
\[ z = \frac{(63 - 65)}{2.5} = -0.8 \]
A negative Z-score indicates that the observation is below the mean. Knowing how to calculate and interpret Z-scores is a fundamental skill in statistics that allows us to compare different data points within the same distribution.
Standard Deviation
Standard deviation is a crucial measure in statistics, quantifying the amount of variation or dispersion in a set of values. A low standard deviation indicates that the values tend to be close to the mean, while a high standard deviation signifies that the values are spread out across a wider range.
To compute the standard deviation, one would typically follow these steps:
  • Find the mean of the data set.
  • Calculate the variance by determining the average of the squared differences from the mean.
  • Take the square root of the variance to get the standard deviation.

In the context of our example with college women's heights, a standard deviation of 2.5 inches means that the majority of women's heights are within 2.5 inches of the mean height of 65 inches, giving us a clear picture of the data's variability.
StatCrunch Software
StatCrunch is a powerful statistical software that offers tools for data analysis, allowing users to perform complex statistical calculations with ease. With its user-friendly interface, StatCrunch helps in calculating probabilities, performing hypothesis tests, and creating visual representations like graphs and charts.
The software is particularly beneficial when working with normal distributions. Users can calculate Z-scores and determine probabilities without needing to refer to traditional Z-score tables. For the given problem, after calculating the Z-score, you could use StatCrunch to find the probability of college women having a height of less than 63 inches simply by using its functions designed for normal probability calculations.
Probability in Statistics
In statistics, probability is the measure of the likelihood that an event will occur. It is quantified as a number between 0 and 1, with 0 indicating impossibility and 1 indicating certainty. Probabilities can also be expressed as percentages, multiplying the number by 100%.
For instance, if using StatCrunch or a normal distribution table, you might find a probability of 0.2119 for women's heights falling below a certain value. To express this as a percentage, simply multiply by 100 to get 21.19%. This means there's a 21.19% chance of randomly selecting a college woman who is shorter than 63 inches, given the normal distribution of the heights.
Normal Distribution Table
A normal distribution table, also known as a Z-table, is a reference for finding probabilities associated with the standard normal distribution. The table displays the probability that a standard normal random variable will be less than or equal to a certain Z-score value.
When you look up a Z-score of -0.8 in the table, it will show the probability of selecting a value less than -0.8. In our example of college women's heights, the table would give you the exact probability that a woman is shorter than 63 inches. Mastering the use of this table is invaluable for students and professionals alike, allowing for quick assessments of statistical data without the need for software in some cases.

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Most popular questions from this chapter

The Normal model \(N(65,2.5)\) describes the distribution of heights of college women (inches). Which of the following questions asks for a probability and which asks for a measurement (and is thus an inverse Normal question)? a. What is the probability that a random college woman has a height of 68 inches or more? b. To be in the Tall Club, a woman must have a height such that only \(2 \%\) of women are taller. What is this height?

Fair Die Toss a fair six-sided die. The probability density function (pdf) in table form is given. Make a graph of the pdf for the die.

Babies in the United States have a mean birth length of \(20.5\) inches with a standard deviation of \(0.90\) inch. The shape of the distribution of birth lengths is approximately Normal. a. How long is a baby born at the 20 th percentile? b. How long is a baby born at the 50 th percentile? ch How does your answer to part b compare to the mean birth length? Why should you have expected this?

Stanford-Binet IQs for children are approximately Normally distributed and have \(\mu=100\) and \(\sigma=15 .\) What is the probability that a randomly selected child will have an IQ of 115 or above?

The distribution of the math portion of SAT scores has a mean of 500 and a standard deviation of 100 , and the scores are approximately Normally distributed. a. What is the probability that one randomly selected person will have an SAT score of 550 or more? b. What is the probability that four randomly selected people will all have SAT scores of 550 or more? c. For 800 randomly selected people, what is the probability that 250 or more will have scores of 550 or more? d. For 800 randomly selected people, on average how many should have scores of 550 or more? Round to the nearest whole number. e. Find the standard deviation for part d. Round to the nearest whole number. f. Report the range of people out of 800 who should have scores of 550 or more from two standard deviations below the mean to two standard deviations above the mean. Use your rounded answers to part \(\mathrm{d}\) and \(\mathrm{e}\). g. If 400 out of 800 randomly selected people had scores of 550 or more, would you be surprised? Explain.

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