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The number of leaves taken per year by employees of an office has a mean of 50 and a standard deviation of 5 . a. What number of leaves corresponds to a \(z\) -score of \(1.25\) ? b. What number of leaves corresponds to a \(z\) -score of \(-1.75\) ?

Short Answer

Expert verified
For a z-score of 1.25, the number of leaves corresponds is 56.25, and for a z-score of -1.75, the number of leaves corresponds is 41.25.

Step by step solution

01

Calculation for a z-score of 1.25

Use the following formula to calculate the equivalent value for a z-score of 1.25, X = Z*σ + µ. Substituting Z=1.25, µ = 50 and σ = 5 gives X = 1.25 * 5 + 50 = 56.25. This means 56.25 leaves correspond to a z-score of 1.25.
02

Calculation for a z-score of -1.75

Similarly, use the equation X = Z*σ + µ to calculate the equivalent value for a z-score of -1.75. Substituting Z=-1.75, µ = 50 and σ = 5 gives X = -1.75 * 5 + 50 = 41.25. This means 41.25 leaves correspond to a z-score of -1.75.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Deviation
Understanding standard deviation is crucial when digging into the depths of data analysis. In simple terms, the standard deviation is a measure that tells us how spread out numbers are in a set of data. It's like looking at a bunch of dots on a graph and seeing how far apart they are. The further apart they are, the higher the standard deviation, indicating more variability in the data.
Imagine a class where everyone scores close to 85 out of 100 on a test. The standard deviation of scores would be low because student performance is very consistent. Now picture another class where scores are all over the place, like a rollercoaster with some students scoring very high and others very low. This class would have a higher standard deviation.

Calculating Standard Deviation

To calculate standard deviation, first, find the mean (average) of the data. Then, subtract the mean from each data point and square the result. Next, average these squared differences, and finally, take the square root of that average. This final step gives us the standard deviation, denoted usually by the Greek letter sigma (σ).
Normal Distribution
When a set of data forms a bell-shaped curve when plotted, we're looking at a normal distribution, also known as a Gaussian distribution. It's an incredibly important concept in statistics because a lot of things we measure in real life, like heights, test scores, or even leaves taken by employees, tend to form this kind of pattern.
In a perfect normal distribution, most data points fall close to the mean, and as we move further away, on either side, the occurrences become less and less frequent. The standard deviation plays a starring role in determining the shape of the curve. A small standard deviation means the data hugs tight around the mean, while a larger one indicates a flatter and wider bell curve.

Properties of a Normal Distribution

  • Symmetry: The left and right sides of the curve are mirror images of each other.
  • Mean, Median, and Mode: In a perfectly normal distribution, all three of these measures of central tendency are the same and lie at the center of the distribution.
  • Tails: The bell curve tails off symmetrically towards infinity on both sides, never actually touching the x-axis.

Empirical Rule

The empirical rule, or the 68-95-99.7 rule, helps assess probabilities in a normal distribution, stating that around 68% of the data falls within one standard deviation of the mean, about 95% falls within two, and 99.7% within three standard deviations.
Data Interpretation
Data interpretation involves making sense of numbers and figures, turning them into information that can be used to make decisions. It's like being a detective looking at clues (data) to solve a mystery (understand a phenomenon or predict outcomes). Through interpretation, we can discover patterns, trends, and relationships within data.
One tool often used is the z-score, which tells us how many standard deviations away from the mean a particular data point is. It's a way to compare apples to apples, or, in our textbook example, how the number of leaves taken by employees stacks up against the office average.

Applying z-scores

If a z-score is positive, the corresponding value is above the mean. Conversely, a negative z-score indicates a value below the mean. In our example, 56.25 leaves is 1.25 standard deviations above the mean, while 41.25 leaves is 1.75 standard deviations below. Such insights can help in performance evaluation, quality control, or even predicting future events based on past data.

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Most popular questions from this chapter

College student Jacqueline Loya asked 50 employed students how many times they went out to eat last week. Half of the students had full-time jobs and half had part-time jobs. Full-time: \(5,3,4,4,4,2,1,5,6,5,6,3,3,2,4,5,2,3,7,5,5,1\), \(4,6,7\) Part-time: \(1,1,5,1,4,2,2,3,3,2,3,2,4,2,1,2,3,2,1,3,3,2\), \(4,2,1\) a. Using the median values, write a sentence comparing the typical numbers of times the two groups ate out. b. Using the interquartile ranges, write a sentence comparing the variability of these two groups.

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The data that follow are final exam grades for two sections of statistics students at a community college. One class met twice a week relatively late in the day; the other class met four times a week at 11 a.m. Both classes had the same instructor and covered the same content. Is there evidence that the performances of the classes differed? Answer by making appropriate plots (including side-by-side boxplots) and reporting and comparing appropriate summary statistics. Explain why you chose the summary statistics that you used. Be sure to comment on the shape of the distributions, the center, and the spread, and be sure to mention any unusual features you observe. 11 a.m. grades: \(100,100,93,76,86,72.5,82,63,59.5,53,79.5\), \(67,48,42.5,39\) 5 p.m. grades: \(100,98,95,91.5,104.5,94,86,84.5,73,92.5,86.5\), \(73.5,87,72.5,82,68.5,64.5,90.75,66.5\)

An expert claims that all things being equal, offices without a reception area tend to sell for less than those with a reception area. What does this statement mean? (Pick the best choice.) a. There are more offices with a reception area than without. b. There is more variability in the price of offices without a reception area than in the price of those with it. c. The less expensive offices sold do not have a reception areas. d. The typical price for offices without a reception area is less than the typical price for offices with a reception area.

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