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Mrs. Diaz has two children: a threeyear-old boy 43 inches tall and a ten-year- old girl 57 inches tall. Three-year-old boys have a mean height of 38 inches and a standard deviation of 2 inches, and ten-year-old girls have a mean height of \(54.5\) inches and a standard deviation of \(2.5\) inches. Assume the distributions of boys' and girls' heights are unimodal and symmetric. Which of Mrs. Diaz's children is more unusually tall for his or her age and gender? Explain, showing any calculations you perform. (Source: www.kidsgrowth.com)

Short Answer

Expert verified
The three-year-old boy of Mrs. Diaz is more unusually tall for his age and gender.

Step by step solution

01

Calculating the Z-score for the boy

Firstly, we will calculate the z-score for the boy, using the formula \( z = \frac{x - \mu}{\sigma} \), where \( x \) is the height of the boy, \( \mu \) is the mean height of other boys his age, and \( \sigma \) is the standard deviation for the height of boys his age. Plugging in the values, we get \( z = \frac{43 - 38}{2} = 2.5 \). So, the z-score for the boy is 2.5.
02

Calculating the Z-score for the girl

Next, we will calculate the z-score for the girl, using the same formula. So, we get \( z = \frac{57 - 54.5}{2.5} = 1.0 \). Therefore, the z-score for the girl is 1.
03

Comparing the calculated Z-scores

Now that we have both z-scores, we can compare them to determine which child is more unusually tall for their age. Since the boy's z-score of 2.5 is higher than the girl's z-score of 1, it means that the boy's height is more unusually tall compared to his peers.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Deviation
Understanding standard deviation is crucial when interpreting data. In essence, it's a measure that quantifies the amount of variation or dispersion of a set of data values. When the data points are spread out over a wider range, the standard deviation is higher, indicating greater variability. Conversely, a low standard deviation suggests that the data points tend to be close to the mean, or expected value.

For example, in the context of height, if we have a group of individuals and they all have heights very close to the average, the standard deviation will be low. If another group has heights that are more spread out — some much taller and some much shorter than the average — their standard deviation will be higher.

In the exercise provided, the standard deviation helps us to understand how the heights of Mrs. Diaz's children compare to those of their peers. Calculations of Z-scores are reliant on these deviations to determine how many standard deviations away from the mean a particular value lies.
Mean
The mean, often referred to as the average, is a critical concept in statistics and is computed by adding up all the values in a set and then dividing by the number of values. It provides a central point in a data set to which individual data points can be compared.

In our exercise involving children's heights, the mean height for three-year-old boys is given as 38 inches, and for ten-year-old girls, it's 54.5 inches. These figures serve as a benchmark to assess individual cases, such as the heights of Mrs. Diaz's children. By comparing their heights to the mean, we can start to gauge whether they are unusually tall or short for their age groups.

However, the mean alone doesn't give us the complete picture. This is where statistical analysis using the Z-score comes into play, combining both the mean and the standard deviation to provide a more nuanced understanding of where an individual data point stands in relation to its peers.
Statistical Analysis
Statistical analysis involves collecting, summarizing, interpreting, and drawing conclusions from data. Within this broad field, the Z-score is a powerful tool that allows us to standardize individual data points, enabling comparisons across different sets of data.

When we calculate the Z-score, as in the steps taken to solve Mrs. Diaz's children's height analysis, we are determining how many standard deviations away from the mean a particular value lies. The Z-score is a dimensionless quantity that tells us where a value sits within a distribution. A positive Z-score indicates a value above the mean, while a negative Z-score indicates a value below.

In the context of the exercise, by calculating the Z-scores for both children, we've conducted a basic form of statistical analysis to compare their heights with others in their respective age and gender groups. This comparison uses Z-scores as a standardized way of stating where each child stands, providing an insight that is much more informative than raw height measurements alone.

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Most popular questions from this chapter

In 2012, the General Social Survey asked respondents how many children they felt would be in an "ideal" family. The histogram contains the data from 1730 people who responded to the survey. a. Approximately what is the mean ideal number of children? Explain how you chose this value. b. What is the approximate value for the median ideal number of children? Describe how you chose this value. c. Find the mean by completing the work that is started below: $$ \bar{x}=\frac{18(0)+43(1)+965(2)+\cdots}{1730} $$ d. Explain how the method in part \(\mathrm{c}\) is related to the usual method of finding the mean, which has all the raw numbers given, without frequencies. e. Which is more appropriate to report for these data, the mean or the median? Why?

College students and surfers Rex Robinson and Sandy Hudson collected data on the self-reported numbers of days surfed in a month for 30 longboard surfers and 30 shortboard surfers. Longboard: \(4,9,8,4,8,8,7,9,6,7,10,12,12,10,14,12,15,13\), \(10,11,19,19,14,11,16,19,20,22,20,22\) Shortboard: \(6,4,4,6,8,8,7,9,4,7,8,5,9,8,4,15,12,10,11,12\), \(12,11,14,10,11,13,15,10,20,20\) a. Compare the typical number of days surfing for these two groups by placing the correct numbers in the blanks in the following sentence: The median for the longboards was for the shortboards was \(\quad\) days, showing that those with boards typically surfed more days in this month. b. Compare the interquartile ranges by placing the correct numbers in the blanks in the following sentence: The interquartile range for the longboards was shortboards was \(\quad\) days, showing more variation in the days surfed this month for the boards.

In 2011 , the mean rate of violent crime (per 100,000 people) for the 10 northeastern states was 314 , and the standard deviation was 118 . Assume the distribution of violent crime rates is approximately unimodal and symmetric. a. Between what two values would you expect to find about \(95 \%\) of the rates? b. Between what two values would you expect to find about \(68 \%\) of the rates? c. If a northeastern state had a violent crime rate of 896 crimes per 100,000 people, would you consider this unusual? Explain. d. If a northeastern state had a violent crime rate of 403 crimes per 100,000 people, would you consider this unusual? Explain.

Name two measures of the center of a distribution, and state the conditions under which each is preferred for describing the typical value of a single data set.

In the recent cricket matches, do you think the standard deviation of the average runs scored by all players in a T-20 match would be larger or smaller than the standard deviation of the average runs scored by all players in a test match? Explain.

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