/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 Tight Control of Blood Sugar "Ti... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Tight Control of Blood Sugar "Tight glycemic control" means that the blood sugar is kept within a narrow range. Read the abstract below, and then answer the questions that follow it. "Methods: In this two-center, prospective, randomized trial, we enrolled 980 children, 0 to 36 months of age, undergoing surgery with cardiopulmonary bypass. Patients were randomly assigned to either tight glycemic control ... targeting a blood glucose level of 80 to \(110 \mathrm{mg}\) per deciliter \(\ldots\) or standard care in the cardiac intensive care unit. Results: A total of 444 of the 490 children assigned to tight glycemic control ( \(91 \%\) ) received insulin versus 9 of 490 children assigned to standard care \((2 \%) \ldots\) [T]ight glycemic control was not associated with a significantly decreased rate of health careassociated infections \((8.6\) vs. \(9.9\) per 1000 patient-days, \(\mathrm{P}=0.67\) ). Conclusions: Tight glycemic control can be achieved with a low hypoglycemia rate after cardiac surgery in children, but it does not significantly change the infection rate \(\ldots .\) as compared with standard care." a. Identify the treatment variable and the response variable. b. Was this a controlled experiment or an observational study? Explain. c. What does the p-value show? d. Can you conclude that the use of tight glycemic control affects the rate of infections? Why or why not?

Short Answer

Expert verified
a. The treatment variable is whether patients are assigned to tight glycemic control or not, and the response variable is the rate of health care-associated infections. b. This is a controlled experiment as patients were randomly assigned to two groups with a variable being manually controlled. c. The p-value of 0.67 reveals no significant difference would be observed due to the treatment. d. No, the use of tight glycemic control does not significantly affect the rate of infections due to a high p-value of 0.67 indicating that the observed effects could be due to random chance.

Step by step solution

01

Identify the treatment variable and the response variable

From the description, the treatment variable, that is the one being manipulated in order to test its effects, is whether patients are assigned to tight glycemic control or standard care. The response variable, the outcome that the researchers were interested in, is the rate of health-care associated infections.
02

Determine if this is a controlled experiment or an observational study

In this case, it is a controlled experiment because the patients are randomly assigned to either tight glycemic control or standard care and the effects on the health care-associated infections are observed.
03

Understand the role of P-value

The P-value is a statistical measure that helps scientists determine whether their hypotheses are correct. In this case, the P-value is 0.67 which suggests that, assuming there was no true effect of the tight glycemic control on the rate of infections, there would be a 67% chance of observing a difference as large as (or larger than) the one in the study due to random sampling variability.
04

Conclude if the use of tight glycemic control affects the rate of infections

The conclusion, based on the data, is that the use of tight glycemic control does not significantly affect the rate of infections. The reason for this is that the p-value is so high (0.67) which means that it is likely that the observed effects could be due to random chance.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Treatment Variable
In a controlled experiment, the treatment variable is the factor that is deliberately changed or manipulated to observe its effect. In our exercise, the treatment variable is the type of care patients receive: tight glycemic control versus standard care. This variable is pivotal because researchers want to assess whether manipulating blood glucose levels can impact other health outcomes, such as the rate of infections. By controlling this variable, researchers aim to isolate its effects and draw a clearer conclusion. Thus, understanding the treatment variable helps determine the direct cause-effect relationship in an experiment.
Response Variable
The response variable, or the dependent variable, is the outcome researchers are interested in measuring. In this exercise, the response variable is the rate of health-care associated infections. The goal of the research is to see if altering the treatment variable affects this response. It is crucial in understanding how changes in the treatment variable can directly or indirectly influence the outcome. By focusing on the response variable, researchers can collect data that may confirm or refute their initial hypothesis concerning the efficacy of the treatment applied.
P-value
A p-value is a statistical measure that helps scientists understand the strength of their experimental results. It quantifies the probability of obtaining results at least as extreme as the ones observed, assuming that the null hypothesis (no effect) is true. In our scenario, the p-value is 0.67. This indicates that there is a 67% chance of observing a change as large as in this study by random chance alone if tight glycemic control truly has no effect on infection rates.
  • Low p-value (typically <0.05) suggests strong evidence against the null hypothesis, indicating a significant effect.
  • High p-value, as in this case, suggests weak evidence against the null hypothesis, so no significant effect is detected.
By understanding the p-value, researchers can better interpret their experimental outcomes in the context of statistical significance.
Statistical Significance
Statistical significance refers to whether the results of an experiment are likely to be true or occurred by random chance. If results are statistically significant, it means they are unlikely to occur if the null hypothesis were true. In the exercise provided, the p-value of 0.67 indicates a lack of statistical significance.
  • Statistical significance helps researchers judge how conclusive their findings are.
  • Without statistical significance, any observed differences can likely be attributed to variability or error in the sample data rather than a real effect.
In this study, since the results are not statistically significant, it implies that tight glycemic control does not have a meaningful impact on infection rates when compared to standard care.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The Perry Preschool Project discussed in Exercises \(10.23-10.25\) found that 8 of the 58 students who attended preschool had at least one felony arrest by age 40 and that 31 of the 65 students who did not attend preschool had at least one felony arrest (Schweinhart et al. 2005). a. Compare the percentages descriptively. What does this comparison suggest? b. Create a two-way table from the data and do a chi-square test on it, using a significance level of \(0.05 .\) Test the hypothesis that preschool attendance is associated with being arrested. c. Do a two-proportion \(z\) -test. Your alternative hypothesis should be that preschool attendance lowers the chances of arrest. d. What advantage does the two-proportion \(z\) -test have over the chisquare test?

Oil Leaders The table shows the world's five largest crude oil producing countries and their total oil output in percentage for the years 2011 and 2012 (www.whichcountry.co). Give two reasons why you should not do a chi-square test with these data.

Funds and Returns In May 2016, the Economic Times reported that "Growth- oriented funds tend to exhibit strong returns within a short span of time." Is this conclusion likely to be the result of an observational study or a controlled experiment? Is it saying that growth-oriented funds lower the risk of low returns?

Removal of Healthy Appendixes Computed tomography (CT) scans are used to diagnose the need for the removal of the appendix. CT scans give the patient a large level of radiation, which has risks, especially for young people. There is a new form of \(\mathrm{CT}\) scanning called low-dose CT, which was tested to see whether it was inferior when diagnosing appendicitis. Negative appendectomies are appendectomies that were done even though the appendix was healthy. The negative appendectomy rate was 6 of 172 patients randomly assigned to the low-dose \(C T\) and 6 out of 186 patients randomly assigned to the standard-dose group. a. Find the negative appendectomy rates for both samples and compare them. b. Test the hypothesis that the negative appendectomy rate and dosage are independent at the \(0.05\) level.

Endocarditis Kang et al. reported on a randomized trial of early surgery for patients with infective endocarditis (a heart infection). Of the 37 patients assigned to early surgery, 1 had a bad result (died, had an embolism, or had a recurrence of the problem within 6 months). Of the 39 patients with conventional treatment (of whom more than half had surgery later on), 11 had a bad result. a. Find and compare the sample percentages of those who had a bad result for each group. b. Create a two-way table with the labels Early Surgery and Conventional across the top. c. Test the hypothesis that early treatment and a bad result are independent at the \(0.05\) level. d. Does the treatment cause the effect? Why or why not? e. Can you generalize to other people? Why or why not? (Source: D. Kang et al. \(2012 .\) Early surgery versus conventional treatment for infective endocarditis. New England Journal of Medicine \(366,2466-2473\), June 28.)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.