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Removal of Healthy Appendixes Computed tomography (CT) scans are used to diagnose the need for the removal of the appendix. CT scans give the patient a large level of radiation, which has risks, especially for young people. There is a new form of \(\mathrm{CT}\) scanning called low-dose CT, which was tested to see whether it was inferior when diagnosing appendicitis. Negative appendectomies are appendectomies that were done even though the appendix was healthy. The negative appendectomy rate was 6 of 172 patients randomly assigned to the low-dose \(C T\) and 6 out of 186 patients randomly assigned to the standard-dose group. a. Find the negative appendectomy rates for both samples and compare them. b. Test the hypothesis that the negative appendectomy rate and dosage are independent at the \(0.05\) level.

Short Answer

Expert verified
a) The negative appendectomy rates for the Low-dose and Standard-dose groups are approximately 0.0349 (or 3.49%) and 0.0323 (or 3.23%) respectively. Therefore, the rates are quite similar. b) The result of the hypothesis test would provide the statistical evidence whether or not the negative appendectomy rate and the type of CT-dose are independent.

Step by step solution

01

Calculate the Negative Appendectomy Rates

Calculate the negative appendectomy rates for the low-dose group and standard-dose group separately. The rate is determined by dividing the number of negative appendectomies by total number of patients in each group. For Low-dose, the rate is \(6/172\) and for the Standard-dose, the rate is \(6/186\).
02

Compare the Rates from both groups

Compare the rates calculated in step 1 to evaluate the observed differences. This can be done by finding the difference between the rates.
03

State the Null and Alternative Hypotheses

The null hypothesis \(H_0\) posits that the negative appendectomy rate and the type of CT scan (low-dose or standard-dose) are independent. The alternative hypothesis \(H_1\) states that they are not independent. In a chi-square test for independence, the Null hypothesis always states that the variables are independent.
04

Setup the Contingency Table and Calculate the Expected Values

Create a 2x2 contingency table and calculate the expected values using the formula \((row total * column total) / overall total\) for each cell.
05

Perform Chi-Square Test for Independence

Calculate the chi-square test statistic using the formula: \(\chi^2 =\sum \frac{(Observed-Expected)^2}{Expected}\). After calculating the statistic, obtain the p-value by comparing the statistic with the chi-square distribution with 1 degree of freedom.
06

Make Decision

Compare the p-value with the significance level (0.05). If p value is less than 0.05, reject the null hypothesis. Otherwise, do not reject the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Negative Appendectomy Rate
Negative appendectomy rate is an important measure when assessing the effectiveness of diagnostic tools, such as CT scans used for appendicitis. This rate is calculated by dividing the number of surgeries performed on healthy appendices by the total number of appendectomies attempted.
For example, in the case of low-dose CT scans, the negative appendectomy rate is found by calculating \(\frac{6}{172}\), resulting in approximately 0.0349, or 3.49%. Similarly, for standard-dose CT scans, the rate is \(\frac{6}{186}\), which is approximately 0.0323, or 3.23%.
It is a valuable metric because it highlights potential misdiagnoses, which leads to unnecessary surgeries. Comparing these rates helps researchers and medical professionals determine if different diagnostic methods significantly affect surgical outcomes.
Chi-Square Test
The Chi-Square Test is a statistical method used to evaluate whether there is a significant association between two categorical variables. In this context, it is used to assess whether the type of CT scan (low-dose or standard-dose) affects the negative appendectomy rate.
To conduct this test, a crucial step involves setting up a contingency table of observed values and calculating the expected frequencies assuming the null hypothesis is true. Then, the Chi-Square statistic is calculated using the formula \[\chi^2 = \sum \frac{(Observed - Expected)^2}{Expected}\].
This statistic measures how much the observed data deviate from what would be expected if there were no association between the variables. The result helps determine whether these deviations are due to chance or if there is a real underlying relationship.
Contingency Table
A contingency table is a type of data table that displays the frequency distribution of variables. It's particularly useful in the Chi-Square Test for independence.
In this scenario, the contingency table is set up with two rows and two columns to represent two groups: low-dose and standard-dose CT scans. One row corresponds to negative appendectomy cases, and the other to non-negative cases.
For example, it might look like this (without using actual tables for explanation):
  • Low-dose CT: 6 negative vs. 166 non-negative
  • Standard-dose CT: 6 negative vs. 180 non-negative
To compute expected frequencies, use the formula: where each cell's expected value is \((row\,total \times column\,total) / overall\,total\). This helps identify whether the observed frequencies are consistent with the assumption of independence.
Null and Alternative Hypotheses
In hypothesis testing, the Null Hypothesis (\(H_0\)) serves as the default assumption that there is no effect or association between the studied variables. Here, it posits that the negative appendectomy rate is independent of the type of CT scan used.
The Alternative Hypothesis (\(H_1\)), on the other hand, suggests that there is an association between the variables. It implies that the negative appendectomy rate does depend on whether a low-dose or standard-dose CT scan is used.
Testing these hypotheses involves calculating a p-value using statistical methods, like the Chi-Square Test, and comparing it against a pre-determined significance level (most often \(0.05\)). This p-value indicates the probability that the observed data would occur under the null hypothesis. A small p-value, typically less than \(0.05\), suggests rejecting \(H_0\), inferring an association.

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