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The 2003 Zagat Restaurant Survey provides food, decor, and service ratings for some of the top restaurants across the United States. For 15 top-ranking restaurants located in Boston, the average price of a dinner, including one drink and tip, was \(\$ 48.60 .\) You are leaving for a business trip to Boston and will eat dinner at three of these restaurants. Your company will reimburse you for a maximum of \(\$ 50\) per dinner. Business associates familiar with these restaurants have told you that the meal cost at one-third of these restaurants will exceed \(\$ 50 .\) Suppose that you randomly select three of these restaurants for dinner. a. What is the probability that none of the meals will exceed the cost covered by your company? b. What is the probability that one of the meals will exceed the cost covered by your company? c. What is the probability that two of the meals will exceed the cost covered by your company? d. What is the probability that all three of the meals will exceed the cost covered by your company?

Short Answer

Expert verified
a) 0.296, b) 0.444, c) 0.222, d) 0.037.

Step by step solution

01

Define Probability of Excessive Cost

Out of the 15 restaurants, one-third exceed the \(50 cost. Therefore, the probability that a randomly selected restaurant's meal exceeds \)50 is \( \frac{1}{3} \). Conversely, the probability that a meal does not exceed $50 is \( 1 - \frac{1}{3} = \frac{2}{3} \).
02

Calculate Probability for None Exceeding Cost

We need to find the probability that none of the meals from three random selections exceed \(50. This can be calculated by raising the probability of a single meal not exceeding \)50 to the power of 3: \( \left( \frac{2}{3} \right)^3 = \frac{8}{27} \approx 0.296 \).
03

Calculate Probability for One Exceeding Cost

To find the probability that exactly one meal exceeds $50, use the binomial probability formula where we seek one "success" (exceeding cost) out of three trials: \( \binom{3}{1} \left( \frac{1}{3} \right)^1 \left( \frac{2}{3} \right)^2 = 3 \times \frac{1}{3} \times \frac{4}{9} = \frac{12}{27} = \frac{4}{9} \approx 0.444 \).
04

Calculate Probability for Two Exceeding Costs

For the probability that exactly two meals exceed $50, again use the binomial formula for 2 "successes": \( \binom{3}{2} \left( \frac{1}{3} \right)^2 \left( \frac{2}{3} \right)^1 = 3 \times \frac{1}{9} \times \frac{2}{3} = \frac{6}{27} \approx 0.222 \).
05

Calculate Probability for All Exceeding Costs

Finally, calculate the probability that all three meals exceed $50 by raising the single meal probability of exceeding to the third power: \( \left( \frac{1}{3} \right)^3 = \frac{1}{27} \approx 0.037 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability Theory is the backbone of predicting outcomes in random events, such as selecting restaurants with meal costs within a budget. In this scenario, we explore the likelihood of different meal cost outcomes using probability. The key to solving such problems is understanding the basic probability rules. Here, for fifteen restaurants, we know that one-third are likely to exceed a certain cost. Thus, the probability for a single restaurant exceeding the cost is \( \frac{1}{3} \), while the probability of it not exceeding the cost is \( \frac{2}{3} \).

With Probability Theory, we can determine the chance of specific combinations of events occurring. For example, if you dine at three different Boston restaurants, you can calculate how many of those meals are likely to go above your company's reimbursement cap using formulas such as the binomial probability formula. This formula helps in calculating events like one, two, or no meals exceeding the cost. By understanding how to apply these probabilities, decisions on restaurant selections become less daunting and more predictable.
Statistical Analysis
Statistical Analysis involves using tools to interpret data and make informed decisions. In this restaurant scenario, binomial distribution plays a crucial role. Binomial distribution helps to model situations where there are two possible outcomes, such as a meal either exceeding or staying under the meal expense cap.

The steps to perform such binomial analysis involve:
  • Identifying the number of trials (three dinners)
  • Defining success probability (meal exceeding cost: \( \frac{1}{3} \))
  • Using the binomial formula \( \binom{n}{k} p^k (1-p)^{n-k} \) to calculate probabilities for specific numbers of successes, where \( n \) is the number of trials and \( k \) is the number of successes
This approach allows you to calculate the probability of different numbers of meals crossing the expense limits. For instance, the probability of one out of three meals exceeding the cap is about 44.4%, showing how data-driven insights can aid in practical scenarios.
Decision Making
Decision Making in the context of dining at these restaurants is informed by a combination of probability insights and statistical analyses. By understanding the likelihood that meals will exceed your budget, you can prepare and adjust your plans accordingly. Decision-making often involves weighing different probabilities and choosing options with the least risk or most favorable outcome.

When faced with such scenarios, analyzing probability outcomes informs the expected expenses. If, for example, there's a 30% chance none of your chosen meals will exceed the cost, but a 44.4% chance that one does, you might decide to budget differently or pick restaurants more selectively. Proper data analysis helps ensure that you're making informed and rational decisions, minimizing potential unexpected expenses. This approach demonstrates how data and statistics enable smarter, more efficient decision-making processes.

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