91Ó°ÊÓ

The subjects are categorized into four groups.

The mathematical formula for expressing probability is:

$P\left(E\right)=\frac{\text{Number}\text{of}\text{favorable}\text{outcomes}}{\text{Total}\text{number}\text{of}\text{outcomes}}$

The measure denotes the chance of getting an event.

The additive totals are computed for each row and column as follows:

The addition rule for two arbitrary events Eand F states that

$P\left(E\text{or}F\right)=P\left(E\right)+P\left(F\right)-P\left(E\text{and}F\right)$

Define A as the event that the randomly selected subject receives vaccine treatment.

Define B as the event that the randomly selected subject developed flu.

The probability that the randomly selected person either received the vaccine treatment or developed flu is expressed as $P\left(A\text{or}B\right)$.

Thus, $P\left(A\text{or}B\right)=P\left(A\right)+P\left(B\right)-P\left(A\text{and}B\right)$ .

The number of subjects that receive the vaccine treatment is 1070.

The number of subjects that developed flu is 109.

The number of subjects that received the vaccine treatment and developed flu is 14.

The total number of subjects recorded is 1602.

The probabilities corresponding to the events can be obtained using the table values as:

$$\begin{gathered} P\left(A\right)=\frac{1070}{1602} \\ P\left(B\right)=\frac{109}{1602} \\ P\left(A\text{and}B\right)=\frac{14}{1602} \end{gathered}$$

Substitute the values in the formula.

The probability that the randomly selected person either received the vaccine treatment or developed flu is computed as follows:

$$\begin{gathered} P\left(A\text{or}B\right)=P\left(A\right)+P\left(B\right)-P\left(A\text{and}B\right) \\ =\frac{1070}{1602}+\frac{109}{1602}-\frac{14}{1602} \\ =0.727 \end{gathered}$$

Thus, the probability that the randomly selected person either received the vaccine treatment or developed flu is 0.727.