91影视

A couple has three children.

The chances of having a girl or a boy are even.

In the event of selecting elements from a sample space,the probability of getting 鈥渁t least one鈥� of a specific type of item is the probability of gettingone or more than one of that item.

The probability of selecting at least one of a unit is the complementary event of selecting none of those.

It also follows the property:

$P\left(\text{at}\text{least}\text{one}\right)=1-P\left(\text{none}\right)$

The sample space for the gender of the three children is as follows:

S = {bbb,bbg,bgb,gbb,bgg,gbg,ggb,ggg}

Here, b represents the male gender, whereas g represents the female gender.

The probability of having at least one girl denotes the probability of having one or more than one girl.

It can also be written as one minus the probability of having no girl.

The number of favorable outcomes of having no girl = 1.

The total number of outcomes = 8.

$$\begin{gathered} P\left(\text{at}\text{least}\text{1}\text{girl}\right)=1-P\left(\text{no}\text{girl}\right) \\ =1-\frac{1}{8} \\ =\frac{7}{8} \\ =0.875 \end{gathered}$$

Therefore, the probability of having at least one girl is equal to 0.875.