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The number of subjects who have Hepatitis C and who do not is tabulated.

The numbers are further divided into positive test results and negative test results.

The probability of theoccurrence of an event subject to a condition that another event has previously occurred is called theconditional probability of the event.

The following is the expression to compute the conditional probability of B, given A.

$P\left(B|A\right)=\frac{P\left(AandB\right)}{P\left(A\right)}$

Let A be the event of selecting a subject who has Hepatitis C.

Let B be the event of selecting a subject who does not have Hepatitis C.

Let C be the event of selecting a subject who has a positive test result.

Let D be the event of selecting a subject who has a negative test result.

The following table consists of the total frequency under each category:

The total number of subjects is 1500.

The number of subjects who do not have Hepatitis C is 1155.

The probability of selecting a subject who does not have Hepatitis C is given by:

$P\left(B\right)=\frac{1155}{1500}$

The number of subjects who do not have Hepatitis C and tested positive is 2.

The probability of selecting a subject who tested positive and does not have Hepatitis C is given by:

$P\left(BandC\right)=\frac{2}{1500}$

The probability of selecting a subject who tested positive, given that he/she does not have Hepatitis C, is calculated as follows:

$$\begin{gathered} P\left(C|B\right)=\frac{P\left(BandC\right)}{P\left(B\right)} \\ =\frac{\frac{2}{1500}}{\frac{1155}{1500}} \\ =\frac{2}{1155} \\ =0.00173 \end{gathered}$$

Therefore, the probability of selecting a subject who tested positive, given that he/she did not have Hepatitis C, is equal to 0.00173.

The event of testing positive, given that the subject does not have Hepatitis C, will bother the subject by worrying him/her gravely.

The subject might need to undergo further testing, which can lead to unnecessary expenses.