/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q6 In Exercises 5鈥8, use the give... [FREE SOLUTION] | 91影视

91影视

In Exercises 5鈥8, use the given information to find the number of degrees of freedom, the critical values L2andR2, and the confidence interval estimate of . The samples are from Appendix B and it is reasonable to assume that a simple random sample has been selected from a population with a normal distribution.

Weights of Pennies 95% confidence;n= 37,s= 0.01648 g.

Short Answer

Expert verified

The degrees of freedom is 36.

The critical values areL2=21.3359 andR2=54.4373.

The 95% confidence interval estimate of is 0.013 g <<0.021 g.

Step by step solution

01

Given information

The size of the sample is n=37.

The sample standard deviation is s=0.01648g.

The level of confidence is 95%.

02

Compute the degrees of freedom, critical values and confidence interval estimate of σ

The degrees of freedom is computed as,

df=n-1=37-1=36

Using the Chi-square table, the critical values are L2=21.3359andR2=54.4373.

The 95% confidence interval estimate of is computed as,

n-1s2R2<<n-1s2L237-10.01648254.4373<<37-10.01648221.33590.013<<0.021

Therefore, the 95% confidence interval estimate of role="math" localid="1648104834948" isrole="math" localid="1648104851448" 0.013g<<0.021g

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Finite Population Correction Factor For Formulas 7-2 and 7-3 we assume that the population is infinite or very large and that we are sampling with replacement. When we sample without replacement from a relatively small population with size N, we modify E to include the finite population correction factor shown here, and we can solve for n to obtain the result given here. Use this result to repeat part (b) of Exercise 38, assuming that we limit our population to a county with 2500 women who have completed the time during which they can give birth.

E=z2p^q^nN-nN-1

n=Np^q^z22p^q^z22+N-1E2

In Exercises 1鈥3, refer to the accompanying screen display that results from the Verizon airport data speeds (Mbps) from Data Set 32 鈥淎irport Data Speeds鈥 in Appendix B. The confidence level of 95% was used

Airport Data Speeds Refer to the accompanying screen display.

a. Express the con铿乨ence interval in the format that uses the 鈥渓ess than鈥 symbol. Given that the original listed data use one decimal place, round the con铿乨ence interval limits accordingly.

b. Identify the best point estimate of and the margin of error.

c. In constructing the con铿乨ence interval estimate of , why is it not necessary to con铿乺m that the sample data appear to be from a population with a normal distribution?

Last Digit Analysis The dotplot below depicts the last digits of the weights of 153 males inData Set 1 鈥淏ody Data.鈥 Do those digits appear to be from a normally distributed population? If not, does the large sample size ofn= 153 justify treating the values as if they were from a normal distribution? Can the sample be used to construct a 95% confidence interval estimate of for the population of all such digits?

Bootstrap Sample.

Here is a random sample of taxi-out times (min) for American Airlines flights leaving JFK airport: 12, 19, 13, 43, 15. For this sample, what is a bootstrap sample?

Critical Thinking. In Exercises 17鈥28, use the data and confidence level to construct a confidence interval estimate of p, then address the given question.

Measured Results vs. Reported Results The same study cited in the preceding exercise produced these results after six months for the 198 patients given sustained care: 25.8% were no longer smoking, and these results were biochemically confirmed, but 40.9% of these patients

reported that they were no longer smoking. Construct the two 95% confidence intervals. Compare the results. What do you conclude?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.