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The data shows the number of vinyl record albums sold for 21 years, listed in chronological order.

The three measures of variation that are most commonly calculated are as follows:

• Range: The difference of the lowest value from the highest.
• Variance: The average squared differences from mean.
• Standard deviation: The square root of variance.

The range of the given sample of 21 years is computed as follows:

$$\begin{gathered} \text{Range}=\text{Highest}\text{Value}-\text{Lowest}\text{Value} \\ =6.1-0.3 \\ =5.8\text{million} \end{gathered}$$

Thus, the range of the number of albums sold is equal to5.80 million.

The sample mean is computed as follows:

$$\begin{gathered} \stackrel{炉}{x}=\frac{{鈭�}_{i=1}^n{x}_i}{n} \\ =\frac{0.3+0.6+....+6.1}{21} \\ =1.80鈥�\text{million} \end{gathered}$$

Thus, the sample mean is equal to 1.80 million.

The variance of the given sample of 21 years is computed as follows:

$$\begin{gathered} s^2=\frac{{鈭�}_{i=1}^n{\left(x_i-\stackrel{炉}{x}\right)}^2}{n-1} \\ =\frac{{\left(0.3-1.80\right)}^2+{\left(0.6-1.80\right)}^2+...+{\left(6.1-1.80\right)}^2}{21-1} \\ =2.09{\left(\text{million}\right)}^2 \end{gathered}$$

Thus, the variance of the number of albums sold is equal to2.09 million square.

The standard deviation of the given sample of 21 years is computed as follows:

$$\begin{gathered} s=\sqrt{s^2} \\ =\sqrt{2.09} \\ =1.44\text{million} \end{gathered}$$

Thus, the standard deviation of the number of albums sold is equal to 1.44 million.

The given sample depictstime-series datarecorded for 21 years in chronological order. The measures of variation express the extent to which data is spread out. They do not provide any meaningful interpretation for the changes that take place in patterns over time.

Thus, the measures of variationdo not tell much about any particular trend in the values over the years.