91影视

Foot lengths are measured in 1988 ANSUR for 11 randomly selected army women.

10.4, 9.3, 9.1, 9.3, 10.0, 9.4, 8.6, 9.8, 9.9, 9.1, 9.1

The lengths are measured in inches.

(a)

The formula for the mean of the sample data is:

$\stackrel{炉}{x}=\frac{鈭�x}{n}$, wherexrepresents the values and nis the count of the values.

Substitute the values in the formula.

$$\begin{gathered} \stackrel{炉}{x}=\frac{10.4+9.3+...+9.1}{11} \\ =\frac{104}{11} \\ 鈮�9.45 \end{gathered}$$

Thus, the mean value is approximately 9.45 inches.

(b)

The formula for the median is:

• Median is the middlemost observation for an odd set of values.
• It can also be the average of the two middlemost observations for an even set of values.

The number of observations is 11.

Arrange the observations in ascending order.

The middlemost observation is 9.30.

The median is given as:

$M=9.30$

Thus, the median is 9.30 inches.

(c)

The value with the maximum frequency is the mode.

The frequency distributions for the foot lengths are:

The highest frequency is obtained for 9.1.

Thus, the mode of the data is 9.1 inches.

(d)

The formula for midrange is:

$\text{Midrange}=\frac{\text{Minimum}\text{value}+\text{Maximum}\text{value}}{2}$

Substitute the values in the formula.

$$\begin{gathered} \text{Midrange}=\frac{8.6+10.4}{2} \\ =\frac{19}{2} \\ =9.5 \end{gathered}$$

Thus, the midrange is 9.50 inches.

The data is known to have been collected in 1988 ANSUR (survey). The data recorded for women then may not represent the women in the army at present.

Thus, the statistics are not considered to be an appropriate representative of the population of army women in the current state.