/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q38 In Exercises 37鈥40, refer to t... [FREE SOLUTION] | 91影视

91影视

In Exercises 37鈥40, refer to the frequency distribution in the given exercise and find the standard deviation by using the formula below, where x represents the class midpoint, f represents the class frequency, and n represents the total number of sample values. Also, compare the computed standard deviations to these standard deviations obtained by using Formula 3-4 with the original list of data values: (Exercise 37) 11.5 years; (Exercise 38) 8.9 years; (Exercise 39) 59.5; (Exercise 40) 65.4.

Standard deviation for frequency distribution

s=nfx2-fx2nn-1

Age (yr) of Best Actor When Oscar Was Won

Frequency

20-29

1

30-39

28

40-49

36

50-59

15

60-69

6

70-79

1

Short Answer

Expert verified

The calculated value of the standard deviation is equal to 9.6 years.

The calculated value of the standard deviation is approximately the same as the given value.

Step by step solution

01

Given information

The data showed the frequencies of the best actors according to their ages when they won the Oscar. The ages are grouped into 7 class intervals.

02

Formula

The formula for calculating thestandard deviation of a frequency distribution is expressed as follows:

s=nfx2-fx2nn-1

Here, f denotes the frequencies;

x denotes the midpoints of the class intervals;

n denotes the total frequency.

03

Calculations

The table below shows the necessary calculations:

Age

(in years)

Midpoint (x)

Frequency (f)

fx

x2

fx2

20-29

24.5

1

24.5

600.25

600.25

30-39

34.5

28

966

1190.25

33327

40-49

44.5

36

1602

1980.25

71289

50-59

54.5

15

817.5

2970.25

44553.75

60-69

64.5

6

387

4160.25

24961.5

70-79

74.5

1

74.5

5550.25

5550.25



n=87

fx=3871.5


fx2=180281.75

The value of standard deviation is calculated as follows, using the values obtained above:

s=nfx2-fx2nn-1=87180281.75-3871.528787-1=9.6

Therefore, the computed standard deviation is equal to9.6 years.

04

Comparison of computed value to the actual value

The actual value of standard deviation is 8.9 years.

Thus, the standard deviation computed from the sample is 9.6 years, which isquite close to the actual value equal to 8.9 years.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Critical Thinking. For Exercises 5鈥20, watch out for these little buggers. Each of these exercises involves some feature that is somewhat tricky. Find the (a) mean, (b) median, (c) mode, (d) midrange, and then answer the given question.

Listed below are prices in dollars for one night at different hotels located on Las Vegas Boulevard (the 鈥淪trip鈥).

If you decide to stay at one of these hotels, what statistic is most relevant, other than the measures of center?

Apart from price, identify one other important factor that would affect your choice.

212 77 121 104 153 264 195 244

Degrees of Freedom Five pulse rates randomly selected from Data Set 1 鈥淏ody Data鈥 in Appendix B have a mean of 78.0 beats per minute. Four of the pulse rates are 82, 78, 56, and 84.

a. Find the missing value.

b. We need to create a list of n values that have a specific known mean. We are free to select any values we desire for some of the n values. How many of the n values can be freely assigned before the remaining values are determined? (The result is referred to as the number of degreesof freedom.)

In Exercises 37鈥40, refer to the frequency distribution in the given exercise and find the standard deviation by using the formula below, where x represents the class midpoint, f represents the class frequency, and n represents the total number of sample values. Also, compare the computed standard deviations to these standard deviations obtained by using Formula 3-4 with the original list of data values: (Exercise 37) 11.5 years; (Exercise 38) 8.9 years; (Exercise 39) 59.5; (Exercise 40) 65.4.

Standard deviation for frequency distribution

s=nf.x2-f.x2nn-1

Age (yr) of Best Actress When Oscar Was Won

Frequency

20-29

29

30-39

34

40-49

14

50-59

3

60-69

5

70-79

1

80-89

1

Arsenic in Rice Listed below are measured amounts (mg per serving) of arsenic in a sample of servings of brown rice [data from the Food and Drug Administration (FDA)]. Construct a frequency distribution. Use a class width of 2 mg, and use 0 mg as the lower class limit of the first class.

6.1 5.4 6.9 4.9 6.6 6.3 6.7 8.2 7.8 1.5 5.4 7.3

In Exercises 21鈥24, find the coefficient of variation for each of the two samples; then compare the variation. (The same data were used in Section 3-1.) 21. Blood Pressure A sample of blood pressure measurements is taken from Data Set 1 鈥淏ody Data鈥 in Appendix B, and those values (mm Hg) are listed below. The values are matched so that 10 subjects each have a systolic and diastolic measurement.

Systolic: 118 128 158 96 156 122 116 136 126 120

Diastolic: 80 76 74 52 90 88 58 64 72 82

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.