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Cola Weights For the four samples described in Exercise 1, the sample of regular Coke has a mean weight of 0.81682 lb, the sample of Diet Coke has a mean weight of 0.78479 lb, the sample of regular Pepsi has a mean weight of 0.82410 lb, and the sample of Diet Pepsi has a mean weight of 0.78386 lb. If we use analysis of variance and reach a conclusion to reject equality of the four sample means, can we then conclude that any of the specific samples have means that are significantly different from the others?

Short Answer

Expert verified

No, it cannot be inferred from the analysis of variance test that which of the specific samples have a statistically significant difference in their sample means.

Step by step solution

01

Given information

Refer to the results in Exercise 1 for establishing the difference between the four sample means. The different sample mean weights are provided for four different samples of cola content. The sample of regular Coke has a mean weight of 0.81682 lb.

The sample of diet Coke has a mean weight of 0.78479 lb.

The sample of regular Pepsi has a mean weight of 0.82410 lb.

The sample of diet Pepsi has a mean weight of 0.78386 lb.

02

Difference in the specific sample means

The analysis of variance tests if there is a difference between the mean of different groups.

Under the analysis of variance test, if there is a significant difference in the sample means due to a factor, it cannot be used to infer which of the samples have a statistically significant difference in their means.

An additional test, such as 鈥楾ukey鈥檚 pairwise comparison test鈥, is conducted to determine which of the specific samples have a significant difference in their means.

Then,by observing the sample means, it can be guessed that there appears to be a difference in the mean weights of the regular samples and diet samples, but this cannot be determined statistically using the ANOVA table.

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Most popular questions from this chapter

Does It Pay to Plead Guilty? The accompanying table summarizes randomly selected sample data for San Francisco defendants in burglary cases (based on data from 鈥淒oes It Pay to Plead Guilty? Differential Sentencing and the Functioning of the Criminal Courts,鈥 by Brereton and Casper, Law and Society Review, Vol. 16, No. 1). All of the subjects had prior prison sentences. Use a 0.05 significance level to test the claim that the sentence (sent to prison or not sent to prison) is independent of the plea. If you were an attorney defending a guilty defendant, would these results suggest that you should encourage a guilty plea?


Guilty Plea

Not Guilty Plea

Sent to Prison

392

58

Not Sent to Prison

564

14

Cola Weights The displayed results from Exercise 1 are from one-way analysis of variance. What is it about this test that characterizes it as one-way analysis of variance instead of two-way analysis of variance?

Speed Dating

Listed below are attribute ratings of males by females who participated in speed dating events (from Data Set 18 鈥淪peed Dating鈥 in Appendix B). Use a 0.05 significance level to test the claim that females in the different age brackets give attribute ratings with the same mean. Does age appear to be a factor in the female attribute ratings?

Age 20-22

38

42

30.0

39

47

43

33

31

32

28

Age 23-26

39

31

36.0

35

41

45

36

23

36

20

Age 27-29

36

42

35.5

27

37

34

22

47

36

32

Lead and Full IQ Scores Example 1 used measured performance IQ scores for three different blood lead levels. If we use the same three categories of blood lead levels with the fullIQ scores, we get the accompanying Excel display. (The data are listed in Data Set 7 鈥淚Q and Lead鈥 in Appendix B.) Using a 0.05 significance level, test the claim that the three categories of blood lead level have the same mean full IQ score. Does it appear that exposure to lead has an effect on full IQ scores?

Pancake Experiment Listed below are ratings of pancakes made by experts (based on data from Minitab). Different pancakes were made with and without a supplement and with different amounts of whey. The results from two-way analysis of variance are shown. Use the displayed results and a 0.05 significance level. What do you conclude?

Whey


0%

10%

20%

30%

No Supplement

4.4

4.5

4.3

4.6

4.5

4.8

4.5

4.8

4.8

4.6

4.7

5.1

Supplement

3.3

3.2

3.1

3.8

3.7

3.6

5.0

5.3

4.8

5.4

5.6

5.3

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