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Find the probability.At Least One. In Exercises \(5-12,\) find the probability. In China, where many couples were allowed to have only one child, the probability of a baby being a boy was 0.545. Among six randomly selected births in China, what is the probability that at least one of them is a girl? Could this system continue to work indefinitely? (Phasing out of this policy was begun in \(2015 .\) )

Short Answer

Expert verified
The probability of at least one girl among six births is 0.9452.

Step by step solution

01

Define the Probability of a Girl

Since the probability of a boy being born is 0.545, the probability of a girl being born is \( P(\text{girl}) = 1 - 0.545 = 0.455 \).
02

Define the Probability of No Girls in Six Births

The probability that no girl is born in six births is \( P(\text{no girl}) = (0.545)^6 \).
03

Calculate the Probability of No Girls

Calculate the value of \( P(\text{no girl}) = (0.545)^6 = 0.0548 \).
04

Calculate the Probability of At Least One Girl

The probability of at least one girl is \( 1 - P(\text{no girl}) = 1 - 0.0548 = 0.9452 \).
05

Conclusion

Thus, the probability that at least one out of six randomly selected births is a girl is approximately 0.9452. Such a system might not be sustainable indefinitely.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability of Events
Probability is a way of quantifying the likelihood of an event. Here, an event can be anything that happens or is expected to happen. The probability of an event is expressed as a number between 0 and 1, where 0 means the event is impossible, and 1 means it is certain. To calculate the probability of an event, we use the formula:
\[ P(\text{event}) = \frac{\text{number of favorable outcomes}}{\text{total number of possible outcomes}} \]
In many real-world cases, understanding probabilities helps in making informed decisions. For example, knowing the probability of rain can help you decide whether to carry an umbrella.
In our exercise, we are dealing with the probability of genders in births. Given that the probability of a baby being a boy in China is 0.545, we can easily find the probability of a baby being a girl by subtracting the boy's probability from 1. This is because the two probabilities must add up to 1.
At Least One
The concept of 'at least one' is incredibly useful in probability calculations. Saying you want the probability of 'at least one' event happening means you are interested in the scenarios where one or more of a particular event occurs.
For instance, in our exercise, we want to know the probability that among six births, there is at least one girl.
The trick to finding 'at least one' probability easily is to use the complementary rule. This rule states that:
`P(at least one) = 1 – P(none)`
Here's why we do this: calculating directly for 'at least one' can sometimes be complicated because it involves many different possibilities. On the other hand, calculating the probability of 'none' is usually straightforward, and then we can simply subtract this value from 1 to get our answer.
So, in our scenario, we first calculate the probability of having no girls out of six births and then subtract this from 1.
Binomial Probability
Binomial probability deals with experiments where there are two possible outcomes – success or failure. In our example, a 'success' is defined as getting a girl, and a 'failure' is getting a boy. The formula for binomial probability is:
\[ P(X=k) = \binom{n}{k} \times p^k \times (1-p)^{n-k} \]
Where:
  • \binom{n}{k} is the binomial coefficient
  • p is the probability of success
  • k is the number of successes
  • n is the total number of trials

In our problem, we could use this formula to find the probability of getting exactly any number of girls in six births, but since we need 'at least one girl', using the complementary method as described earlier is simpler.
Understanding binomial probability is critical in many fields, including genetics, quality control in manufacturing, and even in predicting sports outcomes. It shows how we can model and calculate the probabilities of outcomes over a series of trials.

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Most popular questions from this chapter

Find the probability.At Least One. In Exercises \(5-12,\) find the probability. Subjects for the next presidential election poll are contacted using telephone numbers in which the last four digits are randomly selected (with replacement). Find the probability that for one such phone number, the last four digits include at least one \(0 .\)

Express all probabilities as fractions. As of this writing, the Mega Millions lottery is run in 44 states. Winning the jackpot requires that you select the correct five different numbers between 1 and 75 and, in a separate drawing, you must also select the correct single number between 1 and \(15 .\) Find the probability of winning the jackpot. How does the result compare to the probability of being struck by lightning in a year, which the National Weather Service estimates to be \(1 / 960,000 ?\)

Example 2 in this section includes the sample space for genders from three births. Identify the sample space for the genders from two births.

Express all probabilities as fractions. Your professor has just collected eight different statistics exams. If these exams are graded in random order, what is the probability that they are graded in alphabetical order of the students who took the exam?

Express all probabilities as fractions. The International Morse code is a way of transmitting coded text by using sequences of on/off tones. Each character is 1 or 2 or 3 or 4 or 5 segments long, and each segment is either a dot or a dash. For example, the letter \(G\) is transmitted as two dashes followed by a dot, as in \(--\bullet .\) How many different characters are possible with this scheme? Are there enough characters for the alphabet and numbers?

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