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91Ó°ÊÓ

Find the probability.At Least One. In Exercises \(5-12,\) find the probability. If you make random guesses for 10 multiple choice SAT test questions (each with five possible answers), what is the probability of getting at least 1 correct? If these questions are part of a practice test and an instructor says that you must get at least one correct answer before continuing, is there a good chance you will continue?

Short Answer

Expert verified
The probability of getting at least one correct answer is approximately 0.8926, or 89.26%.

Step by step solution

01

Define the problem

We need to find the probability of getting at least one correct answer out of 10 multiple-choice SAT test questions, each with five possible answers. This is the same as finding the probability of not getting zero correct answers.
02

Determine the probability of a single event

The probability of guessing a single question correctly is \(\frac{1}{5}\) because there is only one correct answer out of five options.
03

Calculate the probability of getting a question wrong

The probability of guessing a single question incorrectly is \(1 - \frac{1}{5} = \frac{4}{5}\).
04

Calculate the probability of guessing all questions wrong

To get all 10 questions wrong, multiply the probability of getting a single question wrong by itself 10 times: \(\bigg( \frac{4}{5} \bigg)^{10}\).
05

Compute the numerical value

Calculate \(\bigg( \frac{4}{5} \bigg)^{10}\) using a calculator: \( \bigg(\frac{4}{5}\bigg)^{10} \approx 0.1074\).
06

Find the probability of getting at least one correct answer

Subtract the probability of getting all questions wrong from 1: \(1 - 0.1074 \approx 0.8926\).
07

Interpret the result

There is approximately an 89.26% chance of getting at least one question correct with random guesses. Therefore, you have a high chance of continuing to the next part of the test.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

probability of success
Understanding the 'probability of success' is key in solving many probability problems, including this one about multiple-choice questions. The probability of success refers to the chance of a desired outcome occurring. In our case, a successful outcome is guessing a multiple-choice question correctly. For multiple-choice questions with five possible answers, the probability of success is \(\frac{1}{5}\), or 20%. This means if you randomly guess an answer, you have a 20% chance of getting it right. Always remember that the probability of success can change based on the number of options or the nature of the questions.
multiple choice questions
Multiple choice questions are common in exams like the SAT. They typically provide several possible answers, only one of which is correct. In this example, each question has five options. This structure allows us to calculate probabilities by determining the chance of guessing correctly or incorrectly. When guessing, each option has an equal likelihood of being chosen. Understanding this helps in calculating the probability for a series of questions. For instance, the chance of guessing wrong for one question is \(1 - \frac{1}{5} = \frac{4}{5} \). Keep in mind that each guess is independent, meaning the outcome of one does not affect another.
binomial probability
Binomial probability is a fundamental concept in statistics used to determine the likelihood of a specific number of successes over a set number of trials. This concept is particularly useful when dealing with multiple-choice questions. To use binomial probability, we need two things: the probability of success on a single trial (e.g., \(p = \frac{1}{5}\)) and the total number of trials (e.g., 10 questions). The binomial probability formula is: \[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \] where: \( n \) = number of trials \( k \) = number of successes \( p \) = probability of success and \( 1-p \) = probability of failure. This formula can determine the probability of any number of correct answers.
statistical methods
Statistical methods help us make sense of data and probabilities. For the multiple-choice problem, several steps were taken to find the solution. First, we identified the problem and recognized the need to calculate a probability. Next, we calculated the probability of success and failure for a single event. Using statistical methods, we extended this to multiple trials (10 questions). The key steps were calculating the probability of getting every question wrong using the formula: \( \bigg( \frac{4}{5} \bigg)^{10} \). Finally, we found the desired probability by subtracting this value from 1. These steps demonstrate the power and clarity that statistical methods bring to solving problems.

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Most popular questions from this chapter

Express all probabilities as fractions. The Digital Pet Rock Company was recently successfully funded via Kickstarter and must now appoint a president, chief executive officer (CEO), chief operating officer (COO), and chief financial officer (CFO). It must also appoint a strategic planning committee with four different members. There are 10 qualified candidates, and officers can also serve on the committee. a. How many different ways can the four officers be appointed? b. How many different ways can a committee of four be appointed? c. What is the probability of randomly selecting the committee members and getting the four youngest of the qualified candidates?

Redundancy in Computer Hard Drives Assume that there is a \(3 \%\) rate of disk drive failures in a year (based on data from various sources including lifehacker.com). a. If all of your computer data is stored on a hard disk drive with a copy stored on a second hard disk drive, what is the probability that during a year, you can avoid catastrophe with at least one working drive? Express the result with four decimal places. b. If copies of all of your computer data are stored on three independent hard disk drives, what is the probability that during a year, you can avoid catastrophe with at least one working drive? Express the result with six decimal places. What is wrong with using the usual round-off rule for probabilities in this case?

Express all probabilities as fractions. In a horse race, a quinela bet is won if you selected the two horses that finish first and second, and they can be selected in any order. The 140 th running of the Kentucky Derby had a field of 19 horses. What is the probability of winning a quinela bet if random horse selections are made?

Use the given probability value to determine whether the sample results could easily occur by chance, then form a conclusion.A study addressed the issue of whether pregnant women can correctly predict the gender of their baby. Among 104 pregnant women, 57 correctly predicted the gender of their baby (based on data from "Are Women Carrying 'Basketballs'. by Perry, DiPietro, Constigan, Birth, Vol. 26, No. 3). If pregnant women have no such ability, there is a 0.327 probability of getting such sample results by chance. What do you conclude?

Express all probabilities as fractions. You want to obtain cash by using an ATM, but it's dark and you can't see your card when you insert it. The card must be inserted with the front side up and the printing configured so that the beginning of your name enters first. a. What is the probability of selecting a random position and inserting the card with the result that the card is inserted correctly? b. What is the probability of randomly selecting the card's position and finding that it is incorrectly inserted on the first attempt, but it is correctly inserted on the second attempt? (Assume that the same position used for the first attempt could also be used for the second attempt.) c. How many random selections are required to be absolutely sure that the card works because it is inserted correctly?

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