/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 10 Express all probabilities as fra... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Express all probabilities as fractions. If radio station call letters must begin with either \(\mathrm{K}\) or \(\mathrm{W}\) and must include either two or three additional letters, how many different possibilities are there?

Short Answer

Expert verified
36504

Step by step solution

01

- Determine the choice for the first letter

The first letter of the radio station call letters can be either \(\text{K}\) or \(\text{W}\). Hence, there are 2 choices for the first letter.
02

- Determine the choices for the additional letters

Each of the additional letters can be any letter from A to Z. This means there are 26 choices for each additional letter.
03

- Calculate the number of combinations for 2 additional letters

When there are 2 additional letters, the number of possible combinations is: \(\text{2 choices for first letter} \times 26 \times 26 = 2 \times 26^2\) Calculating this, we have: \[2 \times 26^2 = 2 \times 676 = 1352\]
04

- Calculate the number of combinations for 3 additional letters

When there are 3 additional letters, the number of possible combinations is: \(\text{2 choices for first letter} \times 26 \times 26 \times 26 = 2 \times 26^3\) Calculating this, we have: \[2 \times 26^3 = 2 \times 17576 = 35152\]
05

- Find the total number of different possibilities

Add the number of combinations for 2 additional letters and 3 additional letters: \[1352 + 35152\] hence, the total number of different possibilities is \[35152 + 1352 = 36504\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

probability calculations
Probability calculations are essential in understanding how likely an event is to occur. In the context of our radio station call letters problem, calculating the number of possible call letters is a part of understanding the overall probability of getting a specific call letter combination.

To illustrate further, consider the two cases of having either 2 or 3 extra letters after the first letter. In each case, we identify the possible outcomes by multiplying the number of choices at each step.
For 2 additional letters, the total outcomes are calculated as:
\[\text{2 choices for the first letter} \times 26 \times 26 = 2 \times 26^2 = 1352\]
Similarly, for 3 additional letters:
\[\text{2 choices for the first letter} \times 26 \times 26 \times 26 = 2 \times 26^3 = 35152\]
Summing these two, we get the total number of possibilities, which stands at 36504. Hence, the probability of any one specific combination, if all combinations are equally likely, would be 1 out of 36504.
combinatorics
Combinatorics is a branch of mathematics that helps us count and arrange objects. In our exercise, combinatorics helps determine the number of possible combinations of call letters based on given criteria.

For example:
  • First letter: 2 choices (either K or W)
  • Each additional letter: 26 choices (A to Z)

The challenge is to combine these choices effectively. The calculation for 2 additional letters involves multiplying the choices:
\[\text{2 choices} \times 26 \times 26 = 2 \times 676\]
For 3 additional letters, it is:
\[\text{2 choices} \times 26 \times 26 \times 26 = 2 \times 17576\]
Adding these results allows us to determine the total number of possible combinations.
elementary statistics
Elementary statistics involves concepts such as counting, basic probability, and understanding data distributions. In our example, we use counting principles to determine the number of possible outcomes for radio call letters.

The steps are straightforward:
  • First, count the choices for the first letter (2 choices).
  • Next, consider the additional letters (26 choices each).
  • Finally, perform calculations for different scenarios (2 and 3 extra letters).

These calculations are simple yet powerful, forming the basis of more complex statistical analysis.
radio station call letters
Radio station call letters are unique identifiers assigned to each station. They typically start with specific letters like K or W and are followed by additional letters.

In the US, stations west of the Mississippi River typically begin with K, while those to the east start with W. This creates a system that is uniquely identifiable and standardized.

For our problem, the combination of having a K or W followed by 2 or 3 additional letters (A-Z) involves a large number of possibilities, reflecting the diverse and widespread nature of radio stations. Calculating these possibilities helps understand the vast number of combinations and highlights the importance of such identifiers in communication.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

In the New Jersey Pick 6 lottery game, a bettor selects six different numbers, each between 1 and 49. Winning the top prize requires that the selected numbers match those that are drawn, but the order does not matter. Do calculations for winning this lottery involve permutations or combinations? Why?

Express all probabilities as fractions. Clinical trials of Nasonex involved a group given placebos and another group given treatments of Nasonex. Assume that a preliminary phase I trial is to be conducted with 12 subjects, including 6 men and 6 women. If 6 of the 12 subjects are randomly selected for the treatment group, find the probability of getting 6 subjects of the same gender. Would there be a problem with having members of the treatment group all of the same gender?

Express all probabilities as fractions. Quicken Loans offered a prize of \(\$ 1\) billion to anyone who could correctly predict the winner of the NCAA basketball tournament. After the "play-in" games, there are 64 teams in the tournament. a. How many games are required to get 1 championship team from the field of 64 teams? b. If you make random guesses for each game of the tournament, find the probability of picking the winner in every game.

Find the probability.At Least One. In Exercises \(5-12,\) find the probability. If you make random guesses for 10 multiple choice SAT test questions (each with five possible answers), what is the probability of getting at least 1 correct? If these questions are part of a practice test and an instructor says that you must get at least one correct answer before continuing, is there a good chance you will continue?

Find the probability.At Least One. In Exercises \(5-12,\) find the probability. It has been reported that \(20 \%\) of iPhones manufactured by Foxconn for a product launch did not meet Apple's quality standards. An engineer needs at least one defective iPhone so she can try to identify the problem(s). If she randomly selects 15 iPhones from a very large batch, what is the probability that she will get at least 1 that is defective? Is that probability high enough so that she can be reasonably sure of getting a defect for her work?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.