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\(P(\mathrm{M})=0.3, P(\mathrm{N})=0.4,\) and events \(\mathrm{M}\) and \(\mathrm{N}\) are mutually exclusive. a. Find \(P(\mathrm{M} \text { and } \mathrm{N}\) ). b. Find \(P(\mathrm{M} \text { or } \mathrm{N}\) ). c. \(\quad\) Find \(P(\mathrm{M} \text { or } \overline{\mathrm{N}})\) d. Find \(P(\mathbf{M} | \mathbf{N})\) e. \(\quad\) Find \(P(\mathbf{M} | \overline{\mathbf{N}})\) f. Are events \(\mathrm{M}\) and \(\mathrm{N}\) independent? Explain.

Short Answer

Expert verified
a) 0, b) 0.7, c) 0.9, d) 0, e) 0.3, f) No, events M and N are not independent because their joint probability does not equal the product of their individual probabilities.

Step by step solution

01

Find P(M and N)

This is the probability of both events M and N occurring. Since M and N are mutually exclusive, this means they cannot occur together. Therefore, \(P(M \text { and } N) = 0\)
02

Find P(M or N)

This is the probability that either event M occurs or event N occurs. Since M and N are mutually exclusive, this is simply the sum of their individual probabilities. Therefore, \(P(M \text { or } N) = P(M) + P(N) = 0.3 + 0.4 = 0.7\)
03

Find P(M or N')

This is the probability that either event M occurs or event N does not occur. Event N not occurring is denoted by N', which means that either N doesn't occur or M does occur. The probability of N' is 1 - P(N) because either event N occurs or it doesn't. Therefore, \(P(M \text { or } N') = P(M) + P(N') = 0.3 + (1 - 0.4) = 0.3 + 0.6 = 0.9\)
04

Find P(M|N) and P(M|N')

These are the probabilities of event M occurring given that event N has occurred (P(M|N)) and event N has not occurred (P(M|N')). Since events M and N are mutually exclusive, the probability of M occurring given N has occurred is 0, because they can't occur together. Similarly, P(M|N') is simply P(M), because the occurrence of N doesn't affect M. Therefore, \(P(M|N) = 0\) and \(P(M|N') = P(M) = 0.3\)
05

Determine if M and N are independent

Two events are independent if the occurrence of one does not affect the probability of the occurrence of the other. The product of their individual probabilities should equal the probability of both occurring. However, since M and N are mutually exclusive, they cannot occur together, so their joint probability is 0. Therefore, \(P(M \text { and } N) = P(M) \times P(N) = 0.3 \times 0.4 = 0.12 \neq 0\). So, events M and N are not independent.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Theory
Probability theory is the branch of mathematics concerned with analyzing random phenomena and quantifying how likely events are to occur. The fundamental concept here is an event, which represents a particular outcome or set of outcomes from some random process. For instance, in a dice roll, one event could be 'rolling a six'.

When calculating probabilities, an event's likelihood is represented as a number between 0 and 1, where 0 means the event is impossible, and 1 means it is certain. The sum of probabilities of all possible outcomes in a given context is always exactly 1. In the given exercise, we have two events, M and N, with defined probabilities of 0.3 and 0.4, respectively.
Conditional Probability
Conditional probability refers to the likelihood of an event occurring given that another event has occurred. This is denoted by the notation \(P(A|B)\), which reads as 'the probability of A given B'. It's a useful concept in situations where the occurrence of one event affects the likelihood of another.

For example, if we have two events, M and N, and we know event N has occurred, we would use conditional probability to determine how that knowledge impacts the probability of event M occurring. However, in our exercise scenario, where M and N are mutually exclusive, the conditional probability of M given N, and that of M given not-N, can be calculated directly. This is because the occurrence of one entirely precludes the occurrence of the other.
Independent Events
Events are independent if the occurrence of one does not influence the probability of the occurrence of the other. In other words, knowing whether one event has occurred provides no information about whether the other has or will occur. A classic example is flipping a fair coin twice; the outcome of the first flip does not affect the outcome of the second.

In probability terms, events A and B are independent if \(P(A \text { and } B) = P(A) \times P(B)\). However, the exercise shows that M and N are mutually exclusive with \(P(M \text { and } N) = 0\), which is different from \(P(M) \times P(N)\), thus proving that M and N are not independent. This distinction is crucial for students to understand when analyzing event relationships.

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