Chapter 7: Problem 8
For exercises \(5-48\), simplify. $$ \frac{14}{x-5}-\frac{9}{x-5} $$
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Chapter 7: Problem 8
For exercises \(5-48\), simplify. $$ \frac{14}{x-5}-\frac{9}{x-5} $$
These are the key concepts you need to understand to accurately answer the question.
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For exercises \(65-68\), evaluate. $$ \sqrt{16} $$
If the force acting on an object is constant, the relationship of the mass of the object, \(x\), and the acceleration of the object, \(y\), is an inverse variation. When the mass is \(1000 \mathrm{~kg}\), the acceleration is \(\frac{4 \mathrm{~m}}{1 \mathrm{~s}^{2}}\). a. Find the constant of proportionality, \(k\). Include the units of measurement. b. Write an equation that represents this relationship. c. Find the acceleration when the mass is \(1500 \mathrm{~kg}\). Round to the nearest tenth.
For exercises \(45-48\), the formula \(R=\frac{U F}{P}\) describes the glomular filtration rate by a kidney \(R\). Is the relationship of the given variables a direct variation or an inverse variation? $$ F \text { and } P \text { are constant; the relationship of } R \text { and } U \text {. } $$
For exercises 11-30, (a) solve. (b) check. $$ \frac{13}{d}-\frac{5}{9}=\frac{1}{6} $$
For exercises 1-10, (a) solve. (b) check. $$ \frac{4}{9} p-\frac{1}{8}=\frac{25}{72} $$
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