/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 For exercises 1-10, (a) solve.... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

For exercises 1-10, (a) solve. (b) check. $$ \frac{2}{9} x+\frac{5}{3}=\frac{5}{9} x+\frac{7}{3} $$

Short Answer

Expert verified
x = -2

Step by step solution

01

- Isolate the variable term

Subtract \( \frac{5}{9} x \) from both sides of the equation to get all the x terms on one side. \[ \frac{2}{9} x - \frac{5}{9} x + \frac{5}{3} = \frac{7}{3} \] Simplify the equation: \[ -\frac{3}{9} x + \frac{5}{3} = \frac{7}{3} \] which simplifies to \[ -\frac{1}{3} x + \frac{5}{3} = \frac{7}{3} \]
02

- Remove the constant term

Subtract \( \frac{5}{3} \) from both sides to isolate the term involving x: \[ -\frac{1}{3} x + \frac{5}{3} - \frac{5}{3} = \frac{7}{3} - \frac{5}{3} \] Simplify the equation: \[ -\frac{1}{3} x = \frac{2}{3} \]
03

- Solve for x

Multiply both sides by \( -3 \) to solve for x: \[ x = -2 \]
04

- Check the solution

Substitute \( x = -2 \) back into the original equation: \[ \frac{2}{9}(-2) + \frac{5}{3} = \frac{5}{9}(-2) + \frac{7}{3} \] Simplify both sides: \[ -\frac{4}{9} + \frac{15}{9} = -\frac{10}{9} + \frac{21}{9} \] which simplifies to \[ \frac{11}{9} = \frac{11}{9} \] The left-hand side equals the right-hand side, confirming the solution as correct.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Isolating Variable Terms
Isolating the variable term is a crucial first step in solving linear equations. The goal is to get all the terms containing the variable on one side of the equation. In our example, we start with:
$$ \frac{2}{9} x + \frac{5}{3} = \frac{5}{9} x + \frac{7}{3} $$
To isolate the variable term, we subtract \(\frac{5}{9} x\) from both sides. This leaves all the x terms on one side and the constants on the other side:
\[ \frac{2}{9} x - \frac{5}{9} x + \frac{5}{3} = \frac{7}{3} \]
Perform the subtraction:
\[ -\frac{3}{9} x + \frac{5}{3} = \frac{7}{3} \]
Which simplifies further to:
\[ -\frac{1}{3} x + \frac{5}{3} = \frac{7}{3} \]
With all x terms on one side, we're ready for the next step.
Simplifying Equations
Simplifying equations helps make them more manageable to solve. Once the variable terms are isolated, we need to simplify by removing constants from the variable side. For our equation, we have:
\[ -\frac{1}{3} x + \frac{5}{3} = \frac{7}{3} \]
To eliminate the \(\frac{5}{3}\) term, subtract \(\frac{5}{3}\) from both sides:
\

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

For exercises 43-58, (a) solve. (b) check. $$ \frac{3}{k}+\frac{7}{18}=\frac{5}{9} $$

For exercises 61-64, the completed problem has one mistake. (a) Describe the mistake in words or copy down the whole problem and highlight or circle the mistake. (b) Do the problem correctly. Problem: The relationship of the number of gallons of gas, \(x\), and the total cost of the gas, \(y\), is a direct variation. If 8 gallons of gas costs \(\$ 24\), find the constant of proportionality. Incorrect Answer: $$ \begin{aligned} &k=x y \\ &k=(8 \mathrm{gal})(\$ 24) \\ &k=\$ 192 \mathrm{gal} \end{aligned} $$

For exercises \(67-82\), use the five steps and a proportion. A survey asked 505 companies whether they would continue to match their employees' contributions to their \(401 \mathrm{k}\) retirement plans. Find the number of companies that will continue to match the contributions. Three out of five employers maintain \(401(\mathrm{k})\) match despite economic crisis. (Source: www.americanbenefitscouncil.org, March 17, 2009)

The relationship of the radius of a circle, \(x\), and the circumference of the circle, \(y\), is a direct variation. The radius of a circle is \(10 \mathrm{~cm}\), and the circumference is \(62.8 \mathrm{~cm}\). a. Find the constant of proportionality, \(k\). b. Write an equation that represents this relationship. c. Find the circumference of a circle with a radius of \(20 \mathrm{~cm}\).

For exercises 79-82, (a) clear the fractions and solve. (b) check. $$ 1=\frac{7}{6} w+\frac{5}{12} $$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.