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91Ó°ÊÓ

Prove the inclusion/exclusion rule for two sets \(A\) and \(B\) by showing that \(A \cup B\) can be partitioned into \(A \cap B\), \(A-(A \cap B)\), and \(B-(A \cap B)\), and then using the addition and difference rules.

Short Answer

Expert verified
To prove the inclusion/exclusion rule for two sets A and B, we first partition A \(\cup\) B into three non-overlapping regions: A \(\cap\) B, A - (A \(\cap\) B), and B - (A \(\cap\) B). Then, using the addition and difference rules, we find the size of each region and sum them to find the size of A \(\cup\) B. This results in the equation |A \(\cup\) B| = |A| + |B| - |A \(\cap\) B|, which is the inclusion/exclusion rule for two sets A and B.

Step by step solution

01

Define Sets A and B

Let A and B be two sets of elements, where A \(\cup\) B represents the union of A and B, A \(\cap\) B represents the intersection of A and B, and A - (A \(\cap\) B) and B - (A \(\cap\) B) represent the elements that are unique to A and B respectively.
02

Partitioning the Sets

In order to partition A \(\cup\) B into the three necessary regions, we observe that any element in A \(\cup\) B must be either in A, in B, or both in A and B. Hence, we show that A \(\cup\) B can be represented as a sum of three disjoint sets: 1. A \(\cap\) B (elements in both A and B) 2. A - (A \(\cap\) B) (elements in A but not in B) 3. B - (A \(\cap\) B) (elements in B but not in A) This partition effectively separates A \(\cup\) B into three non-overlapping regions, where each region contains elements unique to itself only.
03

Proving the Inclusion/Exclusion Rule using Addition and Difference Rules

Now, using the addition and difference rules, we will find the size of each region in the partition, and sum them to find the size of A \(\cup\) B. 1. Size of A \(\cap\) B: |A \(\cap\) B| 2. Size of A - (A \(\cap\) B): |A| - |A \(\cap\) B| (subtracting the overlap in A) 3. Size of B - (A \(\cap\) B): |B| - |A \(\cap\) B| (subtracting the overlap in B) Now, by summing these three regions, we obtain the size of A \(\cup\) B: |A \(\cup\) B| = |A \(\cap\) B| + (|A| - |A \(\cap\) B|) + (|B| - |A \(\cap\) B|) We can simplify this expression by eliminating the extra terms: |A \(\cup\) B| = |A| + |B| - |A \(\cap\) B| This is the Inclusion/Exclusion Rule for two sets A and B. We have successfully proved it using the partitioning method and the addition and difference rules.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Set Theory
Set theory forms the foundation for understanding collections of objects. A set is simply a well-defined collection of distinct elements. In mathematics, sets are commonly denoted using capital letters like \( A \) or \( B \). Each element in a set is unique, which means no repeats are allowed.

There are operations that allow us to combine or relate these sets in useful ways. For instance, the union of two sets, denoted by \( A \cup B \), combines all elements in sets \( A \) and \( B \). The intersection of two sets, \( A \cap B \), contains only those elements that exist in both \( A \) and \( B \). These operations help us navigate and model various logical relationships and connections between groups of items, making set theory a crucial concept in many branches of mathematics.
Partitioning of Sets
Partitioning a set involves dividing it into distinct, non-overlapping subsets that together make up the entire set. In the context of the given problem, when we consider \( A \cup B \), this means breaking it into specific regions:
  • \( A \cap B \)
  • \( A - (A \cap B) \)
  • \( B - (A \cap B) \)
Each of these subsets contains elements unique to it, meaning no element is counted more than once in the total set \( A \cup B \).

This partitioning is essential for clear delineation and analysis, allowing us to understand the composition of complex sets by looking at their more manageable parts. By identifying these disjoint subsets, we simplify the task of applying mathematical principles like the Inclusion-Exclusion Principle.
Addition and Difference Rules
The Addition and Difference Rules are basic but powerful tools in set theory that help us calculate the size of sets.

The Addition Rule allows us to find the total number of elements in the union of two sets. However, to avoid double-counting elements present in both sets, we rely on the Difference Rule, which involves subtracting the size of the intersection from the combined sizes of the sets.

Here's how it works:
  • First, add the sizes of the individual sets, \( |A| + |B| \).
  • To correct for any overlap (elements counted twice), subtract the intersection size, resulting in \( |A| + |B| - |A \cap B| \).
This application of Addition and Difference Rules provides us with the Inclusion-Exclusion Principle, an elegant theorem addressing instances where multiple sets overlap, thus allowing precise computation of their union's total size without overcounting.

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Most popular questions from this chapter

a. How many distinguishable ways can the letters of the word \(M I L L I M I C R O N\) be arranged? b. How many distinguishable arrangements of the letters of \(M I L L I M I C R O N\) begin with \(M\) and end with \(N\) ? c. How many distinguishable arrangements of the letters of MILLIMICRON contain the letters \(C R\) next to each other in order and also the letters \(O N\) next to each other in order?

Assume that birthdays are equally likely to occur in any one of the 12 months of the year. a. Given a group of four people, \(A, B, C\), and \(D\). What is the total number of ways in which birth months could be associated with \(A, B, C\), and \(D ?\) (For instance, \(A\) and \(B\) might have been born in May, \(C\) in September, and \(D\) in February, As another example, \(A\) might have been born in January, \(B\) in June, \(C\) in March, and \(D\) in October.) b. How many ways could birth months be associated with \(A, B, C\), and \(D\) so that no two people would share the same birth month? c. How many ways could birth months be associated with \(A, B, C\), and \(D\) so that at least two people would share the same birth month? d. What is the probability that at least two people out of \(A, B, C\), and \(D\) share the same birth month? e. How large must \(n\) be so that in any group of \(n\) people, the probability that two or more share the same birth month is at least \(50 \mathrm{~g}\) ?

a. How many integers are there from 10 through 99 ? b. How many odd integers are there from 10 through 99 ? c. How many integers from 10 through 99 have distinct digits? d. How many odd integers from 10 through 99 have distinct digits? e. What is the probability that a randomly chosen two-digit integer has distinct digits? has distinct digits and is odd?

An interesting use of the inclusion/exclusion rule is to check survey numbers for consistency. For example, suppose a public opinion polltaker reports that out of a national sample of 1,200 adults, 675 are married, 682 are from 20 to 30 years old, 684 are female, 195 are married and are from 20 to 30 years old, 467 are married females, 318 are females from 20 to 30 years old, and 165 are married females from 20 to 30 years old. Are the polltaker's figures consistent? Could they have occurred as a result of an actual sample survey?

A coin is loaded so that the probability of heads is \(0.7\) and the probability of tails is \(0.3\). Suppose that the coin is tossed twice and that the results of the tosses are independent. a. What is the probability of obtaining exactly two heads? b. What is the probability of obtaining exactly one head? c. What is the probability of obtaining no heads? d. What is the probability of obtaining at least one head?

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