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Consider strings of length \(n\) over the set \(\\{a, b, c, d\\}\). a. How many such strings contain at least one pair of adjacent characters that are the same? b. If a string of length ten over \([a, b, c, d]\) is chosen at random, what is the probability that it contains at least one pair of adjacent characters that are the same?

Short Answer

Expert verified
The total number of strings of length \(n\) over the set \(\{a, b, c, d\}\) is \(4^n\), and the number of strings with at least one pair of adjacent characters that are the same is \(4^n - (4 \cdot 3^{n-1})\). For a string of length ten, the probability of having at least one pair of adjacent characters that are the same is \(1 - \left(\frac{3}{4}\right)^9\).

Step by step solution

01

Part (a): Total number of strings of length n

The first step is finding the total number of possible strings of length \(n\) from the set \(\{a, b, c, d\}\). There are \(4\) choices for each position in the string, and we have \(n\) positions. Using the multiplication principle, we have a total of \(4^n\) possible strings.
02

Part (a): Counting strings without any pair of adjacent characters that are the same

Now we'll determine the number of strings with no adjacent characters being the same. Let's see the possibilities for the first two positions: 1. \(1^{st}\) position: \(4\) possibilities 2. \(2^{nd}\) position: \(3\) possibilities (since it can't be the same as the \(1^{st}\)) Next, the string's third position: 3. \(3^{rd}\) position: \(3\) possibilities (it cannot be the same as the previous character) As we continue building the string, we will always have \(3\) possibilities for the next character since it cannot repeat the previous one. So, for a string of length \(n\), we have \(4 \cdot 3^{n-1}\) strings without any pair of adjacent characters being the same.
03

Part (a): Counting strings with at least one pair of adjacent characters that are the same

We can find the number of strings with at least one pair of adjacent characters that are the same by subtracting the count of strings without any adjacent repetitions from the total number of strings. Thus, we have: Strings with at least one pair of adjacent characters being the same = Total number of strings - Strings with no adjacent characters being the same = \(4^n - (4 \cdot 3^{n-1})\)
04

Part (b): Calculating probability of selecting a string with at least one pair of adjacent characters being the same

In part (b), we have \(n=10\). We will first determine the total number of strings and the number of strings with at least one pair of adjacent characters being the same: Total number of strings = \(4^{10}\) Number of strings with at least one pair of adjacent characters being the same = \(4^{10} - (4 \cdot 3^9)\) Now, to calculate the probability of selecting a string with at least one pair of adjacent characters being the same, we will take the ratio of this number to the total number of strings: $$ Probability = \frac{4^{10} - (4 \cdot 3^9)}{4^{10}} = 1 - \frac{4 \cdot 3^9}{4^{10}} = 1 - \left(\frac{3}{4}\right)^9 $$ So, the desired probability is \(1 - \left(\frac{3}{4}\right)^9\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability
Probability is a fascinating part of combinatorics that helps determine the likelihood of an event happening. When thinking about probability, we often consider the ratio of the number of successful outcomes to the total number of possible outcomes.

In our example exercise, the 'event' is having at least one adjacent pair of identical characters in a string. To find this probability, we need to think about all possible strings and how many of those meet our criteria.

For a string of length ten made up of the characters \(\{a, b, c, d\}\), there are \(4^{10}\) total possible strings. The ones that have at least one pair of adjacent identical characters are those that we are interested in.

To find this, we use the formula:
  • Number of successful strings = Total number of strings - Number of strings without adjacent pairs.
Ultimately, probability helps quantify uncertainty and provides a numerical measure of likelihood which in our case is given by:\[1 - \left(\frac{3}{4}\right)^9\]This signifies a relatively high chance of picking a string with adjacent identical characters.
Adjacent Characters
Adjacent characters in a string refer to two characters that are next to each other. In the context of our exercise, we were particularly interested in instances where these adjacent characters are identical.

Sometimes, constraints related to adjacent characters arise from the need to ensure variety or randomness in constructing sequences. For example, in password generation, you might want to avoid adjacent repetitions for better security.

When solving problems with constraints on adjacency, such as those from our exercise, it's often more direct to count the configurations where the constraints don't apply (i.e., no two adjacent characters are the same) and use this to infer the configurations where the constraints do apply:
  • Start from the total possible sequences.
  • Exclude the sequences with no identical adjacent characters.
Analyzing adjacent characters is particularly useful in combinatorial problems for simplifying calculations.
Strings
A string in discrete mathematics is a sequence of characters or elements. The concept of strings is fundamental for understanding many topics, from coding theory to probability puzzles like the one in our exercise.

Strings can be of varying lengths and consist of characters from a given set, called an alphabet. In our scenario, the alphabet was \(\{a, b, c, d\}\). Length and composition are two important features of strings that drive how we count and analyze them.

Counting strings involves determining how many possible combinations align with given rules. For the exercise, you start with a foundational rule: with four distinct characters and length \(n\), there are \(4^n\) possible strings. Practical tasks like determining secure passwords or data encoding largely depend on these fundamental principles of strings in discrete mathematics.
Discrete Mathematics
Discrete Mathematics is a branch of mathematics dealing with countable, distinct elements. It's like the study of digital signals instead of continuous ones. In our exercise, discrete mathematics helps us deal with finite sets and structures like strings, which are sequences of distinct characters.

A core part of discrete mathematics includes combinatorics—the art of counting without actually enumerating possibilities. This can simplify solving complex problems and includes concepts like permutations and combinations.
  • Permutations involve arranging objects in order where every arrangement counts as different.
  • Combinations matter when the choice matters but not the order.
In the exercise, we're using combinatorial strategies to solve for probabilities and to explore the nature of strings with adjacent characters. Discrete mathematics offers a toolbox for elegantly and effectively dealing with finite structures and achieving solutions.

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Most popular questions from this chapter

a. How many integers from \(\mid\) through 1,000 are multiples of 4 or multiples of 7 ? b. Suppose an integer from 1 through 1,000 is chosen at random. Use the result of part (a) to find the probability that the integer is a multiple of 4 or a multiple of 7 . c. How many integers from I through 1,000 are neither multiples of 4 nor multiples of 7 ?

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