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2\. Verify the first Absorption Law by means of a truth table.

Short Answer

Expert verified
Through the truth table, it's confirmed that for all combinations of A and B, both \(A + AB\) and \(A(A + B)\) are equal to A, hence verifying the Absorption Law.

Step by step solution

01

Understanding the Absorption Law

Firstly, you need to understand the Absorption Law in Boolean Algebra. This law states that for any boolean variables A and B: \(A + AB = A\) and \(A(A + B) = A\). This indicates that A absorbs B.
02

Set up a Truth Table for Variables A and B

You'll create a truth table with two boolean variables A and B. The table will contain four rows, for each combinations of A and B: (0,0), (0,1), (1,0), (1,1).
03

Fill the Truth Table based on Absorption Law Operations

On this step, you'll fill out the columns for the expressions \(A + AB\) and \(A(A + B)\). For each row, perform the AND operation first (as per the precedence rules), then follow with OR operation. The results will show that they are equal to the corresponding A values.
04

Verification of the Absorption Law

Finally, using the filled truth table, verify the Absorption Law. If for all combinations of A and B, the results of \(A + AB\) and \(A(A + B)\) are same as A, then Absorption Law is verified.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Absorption Law
In Boolean Algebra, the Absorption Law plays a crucial role, simplifying expressions and making calculations easier. The Absorption Law can be broken down into two main identities:
  • \( A + AB = A \)
  • \( A(A + B) = A \).
In these expressions, one can observe that B gets absorbed into A. The first identity tells us that adding a product of a variable to the variable itself returns the variable—similar to having A on its own. For example, if A is £1£, the expression \( A + AB \) will always simplify to A, regardless of B's value.
The second part of the law works similarly for multiplication. \( A(A + B) \) simplifies to A because if A is false (0), the entire expression is false. Conversely, when A is true (1), the expression retains the value of A. These identities simplify Boolean expressions significantly, among others things ensuring circuit designs are simpler and more cost-effective.
Truth Table
A truth table is a valuable tool in Boolean Algebra. It allows us to see the truth values of Boolean expressions based on the input from their variables. For the Absorption Law, you construct a truth table to visualize and verify the law involving the variables A and B.
Here's how you approach it:
  • First, list all possible combinations of A and B. Since each variable can be either 0 or 1, there will be four possibilities: (0,0), (0,1), (1,0), and (1,1).
  • Next, calculate the values for \( A + AB \) and \( A(A + B) \) for each combination.
By doing this, you observe that both expressions result in the same value as A in every case. This step-by-step testing proves the validity and efficiency of the Absorption Law intuitively.
Truth tables simplify the complexity of Boolean films and provide clarity, preventing room for assumption-based errors.
Boolean Variables
Boolean variables are the simplest types of data in Boolean Algebra, representing two states, often denoted as 1 (true) or 0 (false). They form the backbone of Boolean expressions in logic circuits and digital systems.
In logic operations, each variable can be combined with others using operations like AND, OR, and NOT.
  • In an OR operation, such as \( A + B \), the result is true if at least one of the variables is true.
  • In an AND operation like AB, the result is true only if both variables are true.
Boolean variables are used in constructing truth tables to evaluate expressions. Moreover, they support a range of laws and theorems, such as the commutative, associative, distributive, and absorption laws. Recognizing and manipulating these variables with Boolean operations is essential for anyone involved in computer science, electronics, and mathematics.

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Most popular questions from this chapter

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