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At the Coffee Stop, you can buy a mug for \(\$ 25\) and then pay only \(\$ 0.75\) per hot drink. a. What is the slope of the equation that models the total cost of refills? What is the real-world meaning of the slope? b. Use the point \((33,49.75)\) to write an equation in point-slope form that models this situation. c. Rewrite your equation in intercept form. What is the real-world meaning of the \(y\)-intercept?

Short Answer

Expert verified
The slope is 0.75, meaning each drink adds $0.75 to the cost. The equation is \(y = 0.75x + 25\), and the \(y\)-intercept (25) is the cost of the mug.

Step by step solution

01

Understand the Problem

You are given the cost structure of buying a mug and paying for refills at a coffee shop. You need to determine the slope, the equation in point-slope form using a given point, and then rewrite it in intercept form.
02

Identify the Slope and its Real-world Meaning

The slope is the rate at which the total cost increases as more drinks are purchased. In this context, the slope is the cost per additional hot drink, which is given as \(\\( 0.75\). This means for each additional drink, the total cost increases by \(\\) 0.75\).
03

Write Equation in Point-Slope Form

The point provided is \((33, 49.75)\), where 33 is the number of drinks and 49.75 is the total cost. The point-slope form of a line is \(y - y_1 = m(x - x_1)\). Substituting \(m = 0.75\), \(x_1 = 33\), and \(y_1 = 49.75\), the equation becomes:\[y - 49.75 = 0.75(x - 33)\]
04

Convert to Slope-Intercept Form

To convert the point-slope equation to slope-intercept form (\(y = mx + b\)), solve for \(y\):\[y - 49.75 = 0.75x - 24.75\]\[y = 0.75x + 25\]Here, the slope \(m = 0.75\) and the \(y\)-intercept \(b = 25\).
05

Interpret the Y-intercept

The \(y\)-intercept, \(b = 25\), represents the initial cost before any drinks are purchased, which is the cost of buying the mug itself. Hence, it's the starting point of the total cost when zero drinks are consumed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Slope and Intercept
In the context of linear equations, the slope and intercept are two crucial elements that help describe a straight line. Let’s think about the Coffee Stop problem where each drink after buying a mug adds to the total cost. The slope, denoted by the symbol \(m\), often represents how steep a line is. In practical terms, it’s the rate of change. Here, the slope is the cost per additional hot drink, \(0.75\) in this scenario. It tells us that for each drink you buy, the cost rises by \(0.75\).

The intercept, on the other hand, is where the line crosses the y-axis. It's often represented with \(b\). In our example, the \(y\)-intercept is \(25\). This value doesn't change with the number of drinks; it represents the fixed cost of buying the mug, even if you buy no drinks at all.

Together, slope and intercept give the complete story: how the cost changes when buying drinks and what you pay initially.
Dive into Point-Slope Form
The point-slope form of a linear equation is handy when you know a point the line passes through and its slope. The formula is \(y - y_1 = m(x - x_1)\). This tells you how to find the relationship between the two variables, x and y, given the slope \(m\) and a point \((x_1, y_1)\).

Using our coffee mug model, let's apply this with the given point \((33, 49.75)\). Here, \(33\) represents the number of drinks, and \(49.75\) is the total cost. With a slope of \(0.75\), you substitute into the formula: \(y - 49.75 = 0.75(x - 33)\). This equation expresses how as you buy more drinks, the total cost adjusts, keeping the connection between purchased quantity and price straightforward.

Point-slope form is useful because it directly ties a specific scenario to a mathematical model.
Real-World Applications of Linear Equations
Linear equations, particularly when expressed in point-slope or slope-intercept form, have diverse real-world applications.

  • Budget Planning: Helps in predicting costs and setting clear expenditure limits based on changing variables like quantity or time.
  • Engineering: Used to model relationships such as speed versus time, where a constant slope may represent acceleration.
  • Economics: Useful in supply-demand modeling or cost-profit analysis, directly impacting decision-making and policy designing.


The Coffee Stop scenario is simple yet powerful, clearly showing how cost adjustments can be modeled dynamically. It's an example used to replicate larger systems where constant and variable costs interplay, enabling better planning and forecasting.
Exploring Mathematical Modeling
Mathematical modeling is the practice of creating equations to solve real-world problems. These models simplify complexities by using mathematical language. For linear equations, the focus often is on relationships that show a consistent rate of change.

In creating the coffee cost model, you've formed a simple representation of a real-life situation. The linear equation modeled here allows Coffee Stop customers to predict their expenditures based on the number of drinks they purchase. This is valuable in budgeting and financial planning.

Mathematical models can range from simple equations like ours to complex systems incorporating multiple variable interactions. They are pivotal in fields ranging from physics to social sciences, assisting in hypothesis testing and insight gain.

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