/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 How many subsets does a set \(S\... [FREE SOLUTION] | 91Ó°ÊÓ

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How many subsets does a set \(S\) with \(n\) elements have? (b)

Short Answer

Expert verified
A set with n elements has \[ 2^n \] subsets.

Step by step solution

01

Understand the Problem

First, understand that the problem is asking for the number of subsets that can be formed from a set with a given number of elements, denoted as n.
02

Apply the Subset Formula

Recall the formula for finding the number of subsets of a set. The number of subsets of a set with n elements is given by: \[ 2^n \]
03

Substitute the Value of n

Substitute the value of n into the formula. For example, if the set has 3 elements (n=3), then the number of subsets is: \[ 2^3 \]
04

Calculate the Number of Subsets

Perform the calculation based on the substituted value. For instance, \[ 2^3 = 8 \]. Therefore, a set with 3 elements has 8 subsets.
05

Generalize the Solution

Summarize the solution generally: Any set with n elements has \[ 2^n \] subsets.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Subset Calculation
Understanding subset calculation is crucial in combinatorics. A 'subset' of a set is any combination of elements from that set, including the empty set and the set itself. For instance, if you have a set \(\text{S} = \{a, b\}\), the subsets are \(\{\}, \{a\}, \{b\}, \{a, b\}\). The formula to calculate the number of subsets is \[{2^n}\], where \(n\) is the number of elements in the set. This formula originates from the fact that each element can either be included or excluded from a subset. Thus, for each of the \(n\) elements, you have 2 choices (include or exclude), resulting in \({2^n}\) possible subsets. To illustrate, if \(n = 3\), then \({2^3 = 8}\). Therefore, a set with 3 elements can form 8 different subsets. This calculation is fundamental in understanding larger concepts in set theory and combinatorics.
Powers of Two
The concept of 'powers of two' plays a significant role in subset calculations. The reason we use \(2^n\) in our subset formula is because each element of the set has exactly two choices: being in a subset or not. In mathematical terms, a power of two refers to numbers of the form \(2^n\), where \(n\) is any non-negative integer. For example, \(2^0 = 1\), \(2^1 = 2\), \(2^2 = 4\), and so on. These powers expand exponentially as \(n\) increases, which is why even a small increment in \(n\) leads to a large increase in the number of subsets. For example, while a set with 3 elements has \({2^3 = 8}\) subsets, a set with 4 elements will have \({2^4 = 16}\) subsets. The beauty of powers of two lies in this exponential growth, making it a powerful and efficient way to understand and compute the number of possible combinations.
Set Theory
Set theory is the branch of mathematical logic that studies sets, which are collections of objects. It's essential for understanding subsets and other combinatorial concepts. A set can have any number of elements, and these elements can be anything from numbers to letters to objects. In our example set, \(\text{S} = \{a, b, c\}\), each element represents a point in the universe of that set. Subsets are just collections of these points, including the empty set and the set itself. The foundational principles of set theory help us understand how sets interact, combine, and relate to each other. It introduces concepts like union, intersection, and complement, which are operations that can be performed on sets to produce new sets. Understanding these concepts allows for deeper comprehension when calculating subsets and applying combinatorial formulas. Essentially, set theory is the bedrock upon which the understanding of subsets and combinatorics is built.

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Most popular questions from this chapter

Problem 47 has a geometric interpretation in a coordinate plane. A lattice path in the plane is a "curve" made up of line segments that either go from a point \((i, j)\) to the point \((i+1, j)\) or from a point \((i, j)\) to the point \((i, j+1),\) where \(i\) and \(j\) are integers. (Thus lattice paths always move either up or to the right.) The length of the path is the number of such line segments. (a) What is the length of a lattice path from (0,0) to \((m, n) ?\) (b) How many such lattice paths of that length are there? (h) (c) How many lattice paths are there from \((i, j)\) to \((m, n),\) assuming \(i, j,\) \(m,\) and \(n\) are integers? (n)

In a part of a city, all streets run either north-south or east-west, and there are no dead ends. Suppose we are standing on a street corner. In how many ways may we walk to a corner that is four blocks north and six blocks east, using as few blocks as possible? (h)

Now some number \(n\) of schools are going to send their baseball teams to a tournament, and each team must play each other team exactly once. Let us think of the teams as numbered 1 through \(n\). (a) How many games does team 1 have to play in? (b) How many games, other than the one with team \(1,\) does team two have to play in? (c) How many games, other than those with the first \(i-1\) teams, does team \(i\) have to play in? (d) In terms of your answers to the previous parts of this problem, what is the total number of games that must be played?

An ordered pair \((a, b)\) consists of two things we call \(a\) and \(b\). We say \(a\) is the first member of the pair and \(b\) is the second member of the pair. If \(M\) is an \(m\) element set and \(N\) is an \(n\) -element set, how many ordered pairs are there whose first member is in \(M\) and whose second member is in \(N\) ? Does this problem have anything to do with any of the previous problems?

What is \(\sum_{i=0}^{n} i\left(\begin{array}{c}n \\ i\end{array}\right) ?\) (Hint: think about how you might use calculus.)

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