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Give an example of: A vector field \(\vec{F}(x, y, z)\) whose divergence is a nonzero constant.

Short Answer

Expert verified
Example: \( \vec{F}(x, y, z) = x\hat{i} + 2y\hat{j} - z\hat{k} \) with divergence 2.

Step by step solution

01

Understanding Divergence

The divergence of a vector field \( \vec{F}(x, y, z) = P(x, y, z)\hat{i} + Q(x, y, z)\hat{j} + R(x, y, z)\hat{k} \) is defined as \( abla \cdot \vec{F} = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} + \frac{\partial R}{\partial z} \). We need this expression to be a nonzero constant.
02

Constructing the Vector Field

To have a constant divergence, each partial derivative when summed needs to result in that constant. Consider choosing \( P(x,y,z) = ax \), \( Q(x,y,z) = by \), and \( R(x,y,z) = cz \), where \( a, b, c \) are constants. This makes the divergence \( a + b + c \).
03

Example of the Vector Field

Pick values for \( a, b, c \) such that their sum is a nonzero constant. For example, let \( a = 1, b = 2, c = -1 \). This makes the vector field \( \vec{F}(x, y, z) = x\hat{i} + 2y\hat{j} - z\hat{k} \).
04

Calculate Divergence for the Example

Compute \( abla \cdot \vec{F} = \frac{\partial (x)}{\partial x} + \frac{\partial (2y)}{\partial y} + \frac{\partial (-z)}{\partial z} = 1 + 2 - 1 = 2 \). The divergence is the constant 2, which is nonzero.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Vector Field
When dealing with a vector field, you are looking at a function that gives a vector for each point in space. Imagine you have a field of tiny arrows, each attached to a point in three-dimensional space. These arrows can point in different directions, and their lengths may vary.
In mathematical terms, a vector field can be defined as \( \vec{F}(x, y, z) = P(x, y, z)\hat{i} + Q(x, y, z)\hat{j} + R(x, y, z)\hat{k} \).
Here, \( P, Q, \) and \( R \) are functions that determine the components of the vector in the x, y, and z directions, respectively.
  • \( \hat{i} \), \( \hat{j} \), and \( \hat{k} \) are unit vectors pointing in the positive x, y, and z directions.
  • A vector field can be visualized in two or three dimensions depending on the complexity needed.
A good example of a vector field in real life might resemble the force exerted by the wind, pointing in different directions with various strengths.
Partial Derivative
The concept of a partial derivative comes into play when dealing with functions with multiple variables. Simply put, a partial derivative measures the rate at which a function changes as one of its variables changes while keeping all others constant. Essentially, it tells us about the slope in the direction of one variable.
For a function \( f(x, y, z) \), the partial derivative with respect to \( x \) is denoted as \( \frac{\partial f}{\partial x} \).
  • This notation highlights that we only focus on changes concerning \( x \).
  • The same logic applies to partial derivatives with respect to \( y \) and \( z \).
Partial derivatives are essential in vector calculus as they help in calculating divergence. In our context, finding these derivatives for each component of the vector field leads to determining how the field’s net flow is changing at each point.
Constant Divergence
Divergence is a scalar value that signifies how much a vector field spreads out from a given point. Imagine if each point in space was a tiny source of air; divergence would measure how much air that point is emitting or absorbing.
When we talk about constant divergence, we're describing a vector field that has the same divergence at every point, which simplifies calculations.
For a vector field \( \vec{F}(x, y, z) = P(x, y, z)\hat{i} + Q(x, y, z)\hat{j} + R(x, y, z)\hat{k} \), its divergence is given by:
\[ abla \cdot \vec{F} = \frac{\partial P}{\partial x} + \frac{\partial Q}{\partial y} + \frac{\partial R}{\partial z} \]To achieve a constant divergence, this sum must equal a consistent value everywhere in the field. For example, if \( a = 1, b = 2, c = -1 \), then the divergence is \( a + b + c = 2 \). This means the vector field is evenly expanding at every point.
Vector Calculus
Vector calculus is an extended field of mathematics that deals with vector fields, and it's fundamental in describing physical phenomena in physics and engineering.
It involves operations such as:
  • Transport operations: Like divergence and curl, which help understand flow and rotation in a field.
  • Integrals: Such as line integrals and surface integrals, which allow the computation of quantities over a path or surface.
  • Gradients: That provide the direction and rate of fastest increase of a scalar field.
These operations deeply interlink and are used especially with vector fields to express multidimensional phenomena, such as fluid flow, electromagnetism, and more complex physical systems.
Understanding these concepts helps grasp how various properties change over space and time in a multidimensional context.

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Most popular questions from this chapter

Are the statements true or false? Give reasons for your answer. Let \(S_{h}\) be the surface consisting of a cylinder of height \(h,\) closed at the top. The curved sides are \(x^{2}+y^{2}=1\) for \(0 \leq z \leq h,\) and the top \(x^{2}+y^{2} \leq 1,\) for \(z=h,\) oriented outward. If \(\vec{F}\) is divergence free, then \(\int_{S_{h}} \vec{F} \cdot d \vec{A}\) is independent of the height \(h\).

Electric charge is distributed in space with density (in coulomb/m \(^{3}\) ) given in spherical coordinates by $$\delta(\rho, \phi, \theta)=\left\\{\begin{array}{ll}\delta_{0}(\text { a constant }) & \rho \leq a \\\0 & \rho>a\end{array}\right.$$ (a) Describe the charge distribution in words. (b) Find the electric field \(\vec{E}\) due to \(\delta .\) Assume that \(\vec{E}\) can be written in spherical coordinates as \(\vec{E}=\) \(E(\rho) \vec{e}_{\rho},\) where \(\vec{e}_{\rho}\) is the unit outward normal to the sphere of radius \(\rho .\) In addition, \(\vec{E}\) satisfies Gauss's Law for any simple closed surface \(S\) enclosing a volume \(W:\) $$\int_{S} \vec{E} \cdot d \vec{A}=k \int_{W} \delta d V, \quad k \text { a constant }$$

Write an iterated integral for the flux of \(\vec{F}\) through the cylindrical surface \(S\) centered on the \(z\) axis, oriented away from the \(z\) -axis. Do not evaluate the integral. $$\begin{array}{l}\vec{F}(x, y, z)=\vec{i}+2 \vec{j}+3 \vec{k} \\\\\quad S: \text { radius } 10, x \geq 0, y \geq 0,0 \leq z \leq 5\end{array}$$

Are the statements true or false? Give reasons for your answer. \(\operatorname{div} \vec{F}\) is a scalar whose value can vary from point to point.

Are the statements true or false? Give reasons for your answer. Let \(W\) be the solid region between the sphere \(S_{1}\) of \(\mathrm{ra}\) dius 1 and \(S_{2}\) of radius \(2,\) both centered at the origin and oriented outward. If \(\vec{F}\) is a vector field in 3 -space, then \(\int_{W} \operatorname{div} \overrightarrow{\boldsymbol{F}} d V=\int_{S_{2}} \overrightarrow{\boldsymbol{F}} \cdot d \overrightarrow{\boldsymbol{A}}-\int_{S_{1}} \overrightarrow{\boldsymbol{F}} \cdot d \overrightarrow{\boldsymbol{A}}\).

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