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Are the statements true or false? Give reasons for your answer. Let \(S_{h}\) be the surface consisting of a cylinder of height \(h,\) closed at the top. The curved sides are \(x^{2}+y^{2}=1\) for \(0 \leq z \leq h,\) and the top \(x^{2}+y^{2} \leq 1,\) for \(z=h,\) oriented outward. If \(\vec{F}\) is divergence free, then \(\int_{S_{h}} \vec{F} \cdot d \vec{A}\) is independent of the height \(h\).

Short Answer

Expert verified
The statement is true; the integral is zero and independent of height.

Step by step solution

01

Understand the Problem

We are given a surface \( S_{h} \) consisting of a cylindrical side with a height \( h \) and a top closed at \( z=h \). The task is to evaluate the independence of the flux integral \( \int_{S_{h}} \vec{F} \cdot d \vec{A} \) with respect to \( h \) when \( \vec{F} \) is a divergence-free vector field.
02

Apply Divergence Theorem

According to the divergence theorem, for a divergence-free vector field \( \vec{F} \), we have:\[ \int_{V} abla \cdot \vec{F} \, dV = \int_{\partial V} \vec{F} \cdot d\vec{A} \]Since \( abla \cdot \vec{F} = 0 \), the volume integral over the enclosed region of \( S_{h} \) is zero. So \( \int_{S_{h}} \vec{F} \cdot d\vec{A} = 0 \).
03

Evaluate Cylinder and Top Contribution

The surface \( S_{h} \) includes both the cylindrical side and the top. The divergence theorem implies that the total flux through these surfaces is zero because the divergence is zero. The side of the cylinder contributes nothing to the integral as it is balanced by the top surface when divergence is zero.
04

Conclude Based on Independence from Height

Since the flux through \( S_{h} \) is zero for any height \( h \), the integral \( \int_{S_{h}} \vec{F} \cdot d\vec{A} \) indeed remains constant (zero) regardless of \( h \). This implies that the statement is true.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Flux Integral
Flux integral is a fundamental concept in vector calculus, often used to measure the flow of a vector field across a surface. In simpler terms, it calculates how much of a field goes through a given surface. To understand this, imagine a sheet in a breeze—flux integral measures how much wind crosses through the sheet.
The mathematical representation is\[\int_{S} \vec{F} \cdot d\vec{A}\]where:
  • \(\vec{F}\) is the vector field.
  • \(d\vec{A}\) is the vector normal to the surface area \(S\).
This calculation is crucial when determining properties like the independence of flux from certain parameters, such as the height of a cylindrical surface.
Divergence-Free Vector Field
A divergence-free vector field is a field where the divergence at every point is zero. Divergence, in vector calculus, measures the magnitude of a source or sink at a given point. A perfect example is the flow of an incompressible fluid, like water—if no water is added or removed, the flow maintains balance.
Mathematically, a vector field \(\vec{F}\) is divergence-free if:\[abla \cdot \vec{F} = 0\]This property simplifies calculations like flux integrals because, thanks to the Divergence Theorem, the total flux across a closed surface for such fields is zero. Hence, their flux integral over any closed surface is constant and independent of changes in parameters like surface dimensions.
Cylindrical Surface
A cylindrical surface is a three-dimensional geometric shape with straight parallel sides and a circular or oval cross-section. In many calculus problems, we deal with vertical cylinders where the sides are defined by circles, as illustrated by equations like \(x^2 + y^2 = 1\).
Consider the surface \(S_{h}\):
  • It has curved sides that stretch vertically from \(z=0\) to \(z=h\).
  • The top part is a disk at \(z = h\).
These properties make cylindrical surfaces common in issues involving volumetric and surface integrals, facilitating the evaluation of properties due to their geometric symmetry.
Surface Integral
Surface integrals extend the concept of integrals to functions over a surface in three dimensions. Essentially, they accumulate quantities across a surface, such as flux, by summing up all the little pieces of the function over the surface.
The basic formula for a surface integral of a vector field \(\vec{F}\) over a surface \(S\) is:\[\int_{S} \vec{F} \cdot d\vec{A}\]Here, each element of the integral \(d\vec{A}\) is a tiny vector perpendicular to the surface at each point. This calculation is very handy, especially in electromagnetic fields, to determine the total effect of a field through surfaces. In the context of the given exercise, understanding surface integrals is pivotal in evaluating how the surface conditions, like body orientation and boundaries, influence the resulting calculations.

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Most popular questions from this chapter

Are the statements true or false? Give reasons for your answer. If \(\vec{A}(x, y)\) is the area vector for \(z=f(x, y)\) oriented upward and \(\vec{B}(x, y)\) is the area vector for \(z=-f(x, y)\) oriented upward, then \(\vec{A}(x, y)=-\vec{B}(x, y)\)

Consider the flux of the vector field \(\vec{F}=\vec{r} /\|\vec{r}\|^{p}\) for \(p \geq 0\) out of the sphere of radius 2 centered at the origin. (a) For what value of \(p\) is the flux a maximum? (b) What is that maximum value?

Give an example of: A nonzero vector field \(\vec{F}(x, y, z)\) whose divergence is zero.

Electric charge is distributed in space with density (in coulomb/m \(^{3}\) ) given in spherical coordinates by $$\delta(\rho, \phi, \theta)=\left\\{\begin{array}{ll}\delta_{0}(\text { a constant }) & \rho \leq a \\\0 & \rho>a\end{array}\right.$$ (a) Describe the charge distribution in words. (b) Find the electric field \(\vec{E}\) due to \(\delta .\) Assume that \(\vec{E}\) can be written in spherical coordinates as \(\vec{E}=\) \(E(\rho) \vec{e}_{\rho},\) where \(\vec{e}_{\rho}\) is the unit outward normal to the sphere of radius \(\rho .\) In addition, \(\vec{E}\) satisfies Gauss's Law for any simple closed surface \(S\) enclosing a volume \(W:\) $$\int_{S} \vec{E} \cdot d \vec{A}=k \int_{W} \delta d V, \quad k \text { a constant }$$

An infinitely long straight wire lying along the \(z\) -axis carries an electric current \(I\) flowing in the \(\vec{k}\) direction. Ampere's Law in magnetostatics says that the current gives rise to a magnetic field \(\vec{B}\) given by $$\vec{B}(x, y, z)=\frac{I}{2 \pi} \frac{-y \vec{i}+x \vec{j}}{x^{2}+y^{2}}$$

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