Chapter 15: Problem 42
Let \(f(x, y)=80 /(x y)+20 y+10 x+10 x y\) in the region \(R\) where \(x, y>0\). (a) Explain why \(f(x, y)>f(2,1)\) at every point in \(R\) where (i) \(\quad x>20\) (ii) \(\quad y>20\) (iii) \(x<0.01\) and \(y \leq 20\) (iv) \(y<0.01\) and \(x \leq 20\) (b) Explain why \(f\) must have a global minimum at a critical point in \(R\). (c) Explain why \(f\) must have a global minimum in \(R\) at the point (2,1).
Short Answer
Step by step solution
Evaluate f(2,1)
Step 2a: Analyze scenario \(x > 20\)
Step 2b: Analyze scenario \(y > 20\)
Step 2c: Analyze scenario \(x < 0.01\) and \(y \leq 20\)
Step 2d: Analyze scenario \(y < 0.01\) and \(x \leq 20\)
Explain existence of global minimum at critical point
Explain global minimum at (2,1)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Function Analysis
- Understanding the influence of the terms like \( \frac{80}{xy} \), \( 20y \), \( 10x \), and \( 10xy \) as \( x \) and \( y \) vary.
- Recognizing which terms dominate as \( x \) or \( y \) become very large or very small, significantly affecting function values.
Critical Points
Global Minimum
- As \( x \) or \( y \) become extremely large or small, \( f(x, y) \) becomes much larger than 100.
- At point \((2, 1)\), \( f(x, y) = 100 \), which was verified to be smaller than the function's value at other tested points.
Continuity and Unboundedness
- The function \( f(x, y) \) is continuous within \( R \), implying that as \( x \) and \( y \) change slightly, \( f(x, y) \) also changes smoothly.
- Unboundedness refers to the function's potential to reach infinitely large values if \( x \) or \( y \) approach boundary conditions like zero.