/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 41 Find the least squares line for ... [FREE SOLUTION] | 91Ó°ÊÓ

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Find the least squares line for the data points (0,4),(1,3),(2,1).

Short Answer

Expert verified
The least squares line equation is \( y = -1.5x + 4.167 \).

Step by step solution

01

Determine the Sums

First, find the necessary sums for the computation: sum of x-values, sum of y-values, sum of x squared, and sum of xy products. Using the points (0,4), (1,3), and (2,1), we have:\[ \sum x = 0 + 1 + 2 = 3, \sum y = 4 + 3 + 1 = 8 \]\[ \sum x^2 = 0^2 + 1^2 + 2^2 = 5, \sum xy = 0\cdot4 + 1\cdot3 + 2\cdot1 = 5 \]
02

Apply the Least Squares Formula for the Slope

Use the formula for the slope (m) of the least squares line:\[ m = \frac{n(\sum xy) - (\sum x)(\sum y)}{n(\sum x^2) - (\sum x)^2} \]Plugging in the values, \(n=3\), we get:\[ m = \frac{3(5) - (3)(8)}{3(5) - 3^2} = \frac{15 - 24}{15 - 9} = \frac{-9}{6} = -1.5 \]
03

Calculate the y-intercept

Use the formula for the y-intercept (b) of the least squares line:\[ b = \frac{(\sum y) - m(\sum x)}{n} \]Substitute the known values and the calculated slope \(m = -1.5\):\[ b = \frac{8 - (-1.5)(3)}{3} = \frac{8 + 4.5}{3} = \frac{12.5}{3} \approx 4.167 \]
04

Write the Equation of the Least Squares Line

Combine the computed slope and y-intercept into the equation of the line:\[ y = mx + b \]Substituting \(m = -1.5\) and \(b \approx 4.167\), the equation becomes:\[ y = -1.5x + 4.167 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Regression
Linear regression is a statistical method used to model the relationship between a dependent variable and one or more independent variables. The method helps us to understand and predict phenomena by fitting a straight line through a set of data points. This line summarizes the trend of the data in the simplest form. Linear regression is a cornerstone technique in data science and is widely used in economics, biology, and engineering.
The foundational goal of linear regression is to find the best-fitting line, known as the regression line, to ensure it minimizes the deviations of predicted values from the actual data points. One effective way to determine this line is by using the least squares method, which minimizes the sum of squared differences between the observed and predicted values.
In our example, the least squares method is used to find the regression line for data points (0,4), (1,3), and (2,1). This involves computing the line's slope and the y-intercept, which then allow us to write the equation of the line in the form of \(y = mx + b\).
Data Points
Data points are the individual measurements or observations plotted on a graph. In the context of linear regression, these points are used to derive the best-fitting line. Each data point is defined by a pair of values: one that lies on the x-axis and another that lies on the y-axis.
Think of data points as coordinate pairs that connect what you know (independent variable) with what you wish to predict (dependent variable). For the problem at hand, our data points are (0,4), (1,3), and (2,1). Each point provides insight into its respective x (independent) and y (dependent) values.
Analyzing these points helps us to comprehend patterns and relationships, and this understanding is crucial for predicting future observations and for decision-making based on historical data trends.
Slope Calculation
The slope of a line in a linear regression context represents the rate of change between the dependent and independent variables. It shows how much the dependent variable (y) is expected to change for a one-unit change in the independent variable (x). Calculating the slope is a vital part in constructing a least squares regression line.
To determine the slope, the formula used is much like computing the average change, encapsulated as:
\[ m = \frac{n(\sum xy) - (\sum x)(\sum y)}{n(\sum x^2) - (\sum x)^2} \]
In this formula, the symbols \(\sum\) indicate summation over the provided data points, and \(n\) is the number of data points. For the data points (0,4), (1,3), and (2,1), the computed sums lead to a slope of \(m = -1.5\). This negative slope suggests a downward trend, indicating that as x increases, y decreases. Understanding the slope is crucial, as it directly influences the orientation and steepness of the regression line.
Y-Intercept Calculation
The y-intercept is another crucial component of the linear equation, and it represents the point where the regression line crosses the y-axis. In other words, it's the value of \(y\) when \(x = 0\).
Calculating the y-intercept uses the formula:
\[ b = \frac{(\sum y) - m(\sum x)}{n} \]
In this calculation, the slope \(m\) that was previously determined is used. For our data points, substituting \(m = -1.5\) and the calculated sums leads to a y-intercept \(b \approx 4.167\).
This intercept gives us a baseline level of the dependent variable when the independent variable is zero, enabling us to craft a full linear equation: \(y = -1.5x + 4.167\). The y-intercept is not just a mathematical necessity; it can also hold practical significance by providing insights into settings where the independent factor is absent.

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Most popular questions from this chapter

The Dorfman-Steiner rule shows how a company which has a monopoly should set the price, \(p,\) of its product and how much advertising, \(a\), it should buy. The price of advertising is \(p_{a}\) per unit. The quantity, \(q\), of the product sold is given by \(q=K p^{-E} a^{\theta},\) where \(K>0, E>1\) and \(0<\theta<1\) are constants. The cost to the company to make each item is \(c\) (a) How does the quantity sold, \(q\), change if the price, \(p,\) increases? If the quantity of advertising, \(a,\) increases? (b) Show that the partial derivatives can be written in the form \(\partial q / \partial p=-E q / p\) and \(\partial q / \partial a=\theta q / a\). (c) Explain why profit, \(\pi\), is given by \(\pi=p q-c q-p_{a} a\). (d) If the company wants to maximize profit, what must be true of the partial derivatives, \(\partial \pi / \partial p\) and \(\partial \pi / \partial a ?\) (e) Find \(\partial \pi / \partial p\) and \(\partial \pi / \partial a\). (i) Use your answers to parts (d) and (e) to show that at maximum profit, $$\frac{p-c}{p}=\frac{1}{E} \quad \text { and } \quad \frac{p-c}{p_{a}}=\frac{a}{\theta q}$$ (g) By dividing your answers in part ( \(f\) ), show that at maximum profit, $$\frac{p_{a} a}{p q}=\frac{\theta}{E}$$ This is the Dorfman-Steiner rule, that the ratio of the advertising budget to revenue does not depend on the price of advertising.

Does the function have a global maximum? A global minimum? $$h(x, y)=x^{3}+y^{3}$$

Explain what is wrong with the statement. If \(f_{x}=f_{y}=0\) at \((1,3),\) then \(f\) has a local maximum or local minimum at (1,3).

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