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Write the indicated related-rates equation. $$ f=3 x \text { ; relate } \frac{d f}{d t} \text { and } \frac{d x}{d t} $$

Short Answer

Expert verified
\( \frac{df}{dt} = 3 \cdot \frac{dx}{dt} \) is the related-rates equation.

Step by step solution

01

Introduction to Related Rates Equation

In problems involving related rates, we find the relationship between two or more variables that are changing with respect to time. Here, we are given the function \( f = 3x \) and need to relate the rates \( \frac{df}{dt} \) and \( \frac{dx}{dt} \).
02

Differentiate with Respect to Time

To find the relationship between the rates, we differentiate the equation \( f = 3x \) with respect to time \( t \). This means we apply the derivative operator \( \frac{d}{dt} \) to both sides of the equation. The derivative of \( f \) with respect to \( t \) is \( \frac{df}{dt} \), and using the chain rule, the derivative of \( 3x \) with respect to \( t \) is \( 3 \cdot \frac{dx}{dt} \).
03

Formulate the Related Rates Equation

After differentiating, we obtain the related rates equation \( \frac{df}{dt} = 3 \cdot \frac{dx}{dt} \), which shows how the rate of change of \( f \) is related to the rate of change of \( x \). This equation summarizes the relationship between the rates of change of the two functions with respect to time.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Differentiation
Differentiation is a fundamental concept in calculus that deals with finding the rate at which a function changes. In simpler terms, it's all about understanding how one quantity changes with respect to another. In the context of the original exercise, we start with the function \( f = 3x \) and wish to understand how \( f \) changes as the variable \( x \) changes over time.

The operation of finding a derivative, denoted as \( \frac{d}{dt} \), is key here. It indicates how much \( f \) will change in infinitesimally small intervals of time \( t \). Differentiating the function \( f = 3x \) with respect to time helps us uncover the hidden relationship between these changes, which is what we're usually interested in when solving related rates problems.
Chain Rule
The chain rule is an essential tool in calculus that assists us when we have functions nested within other functions, or when we want to differentiate a composite of two or more functions. In our example, when differentiating \( f = 3x \) with respect to \( t \), we actually derive the chain rule.

The chain rule states that if you have a function \( f(g(t)) \), then the derivative with respect to \( t \) is \( \frac{df}{dt} = \frac{df}{dg} \cdot \frac{dg}{dt} \). In our case, \( f \) directly depends on \( x \), which is then influenced by time \( t \). Thus, the derivative \( \frac{d}{dt}(3x) \) involves multiplying the derivative of \( 3x \) with respect to \( x \) by \( \frac{dx}{dt} \), resulting in \( 3 \cdot \frac{dx}{dt} \).

The chain rule is particularly handy when dealing with complex functions, breaking it down into simpler, more manageable pieces.
Derivatives with Respect to Time
In related rates problems, derivatives with respect to time help us understand how different variables change in relation to each other as time progresses. Here, each variable can be thought of as a moving piece, and we're trying to see how one motion affects the other.

In the given exercise, we have \( \frac{df}{dt} \) representing the rate at which \( f \) changes over time, and \( \frac{dx}{dt} \) showing how \( x \) changes over time. The related rates equation we derive, \( \frac{df}{dt} = 3 \cdot \frac{dx}{dt} \), provides a mathematical depiction of how the change in \( f \) can be captured by the change in \( x \) based on their dependency through time.

Understanding derivatives with respect to time is crucial for analyzing real-world situations where variables change simultaneously, such as speed, growth, and other dynamic systems. It allows us to model and predict how one quantity influences another.

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Most popular questions from this chapter

Landfill Usage (Historic) The yearly amount of garbage (in million tons) taken to a landfill outside a city during selected years from 1980 through 2010 is given below. Landfill Usage: Annual Amount of Garbage Taken to a Landfill $$ \begin{array}{|c|c|} \hline \text { Year } & \begin{array}{c} \text { Garbage } \\ \text { (million tons) } \end{array} \\ \hline 1980 & 81 \\ \hline 1985 & 99 \\ \hline 1990 & 115 \\ \hline 1995 & 122 \\ \hline 2000 & 132 \\ \hline 2005 & 145 \\ \hline 2010 & 180 \\ \hline \end{array} $$ a. Using the table values only, identify during which 5 year period the amount of garbage showed the slowest increase. What was the average rate of change during that 5 -year period? b. Write a model for the data. c. Locate the input of the point of slowest increase. How is this input located using the first derivative? How is this input located using the second derivative? d. In what year was the rate of change of the yearly amount of garbage the smallest? What was the rate of increase in that year?

Write the indicated related-rates equation. $$ g=e^{3 x} ; \text { relate } \frac{d g}{d t} \text { and } \frac{d x}{d t} $$

Senior Population (Projected) The U.S. Bureau of the Census prediction for the percentage of the population 65 years and older can be modeled as $$ \begin{aligned} p(x)=&-0.00022 x^{3}+0.014 x^{2} \\ &-0.0033 x+12.236 \text { percent } \end{aligned} $$ where \(x\) is the number of years since \(2000,\) data from \(0 \leq x \leq 50\) (Source: Based on data from U.S. Census Bureau, National Population Projections, \(2008 .)\) a. Determine the year between 2000 and 2050 in which the percentage is predicted to be increasing most rapidly, the percentage at that time, and the rate of change of the percentage at that time. b. Repeat part \(a\) for the most rapid decrease.

For Activities 5 through \(10,\) given the units of measure for production and the units of measure for cost or revenue a. Write the units of measure for the indicated marginal. b. Write a sentence interpreting the marginal as an increase. Revenue is given by \(R(q)\) thousand dollars when \(q\) hundred units are sold; \(R^{\prime}(16)=0.15 .\)

For Activities 5 through \(10,\) given the units of measure for production and the units of measure for cost or revenue a. Write the units of measure for the indicated marginal. b. Write a sentence interpreting the marginal as an increase. Revenue is given by \(R(q)\) million dollars when \(q\) billion units are sold; \(R^{\prime}(4)=2\).

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