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91Ó°ÊÓ

For Activities 5 through \(10,\) given the units of measure for production and the units of measure for cost or revenue a. Write the units of measure for the indicated marginal. b. Write a sentence interpreting the marginal as an increase. Revenue is given by \(R(q)\) million dollars when \(q\) billion units are sold; \(R^{\prime}(4)=2\).

Short Answer

Expert verified
Units of measure: million dollars per billion units. At 4 billion units sold, revenue increases by 2 million dollars for each additional billion units.

Step by step solution

01

Identify the Units for the Marginal

The given function is a revenue function, \(R(q)\), where revenue is measured in million dollars and \(q\) represents the number of units in billion. The marginal revenue, \(R'(q)\), is a derivative with respect to \(q\), hence its units will be the units of revenue divided by the units of quantity, which is \(\text{million dollars per billion units}\).
02

Interpret the Marginal Revenue as an Increase

Given that \(R'(4) = 2\), it means that when selling 4 billion units, the revenue is increasing by 2 million dollars for each additional billion units sold. In simpler terms, if the company sells one more billion units beyond 4 billion, its revenue will increase by 2 million dollars.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Units of Measurement
When dealing with functions in economics, especially those related to revenue and cost, understanding how different quantities are measured is crucial. In economics, the units of measurement often reflect large scales, which may seem unconventional at first.

In the given problem, the revenue function is denoted by \( R(q) \), where revenue is measured in *million dollars* and the quantity \( q \) is measured in *billion units*. This means if you sell one unit added to the billion, you multiply every outcome effect by a billion.

The use of these units is important because it standardizes data and makes it easier for businesses to analyze their financial performance, provide reports, and make decisions. For the derivative, or the marginal revenue \( R'(q) \), it’s crucial to combine these units. The marginal revenue's units are given by dividing the units of revenue (million dollars) by the units of quantity (billion units), providing a result in million dollars per billion units.

So, if you come across a statement saying that the revenue from selling \( q \) billion units is \( R(q) \) million dollars, you now understand the magnitude and importance each term holds.
Interpretation of Derivatives
The derivative in the context of a revenue function provides powerful insights related to changes and trends in revenue as output varies. In simpler terms, it's about understanding how revenue changes as we change the number of units sold.

When examining the given derivative \( R'(4) = 2 \), this means at precisely the point where 4 billion units are sold, any small increase in quantity sold, in this case for each additional billion unit, results in a revenue increase of 2 million dollars.
  • When \( q = 4 \), selling an extra billion units means a revenue rise of 2 million dollars.
  • This understanding helps businesses estimate how beneficial it is to produce and sell one more unit (a whole billion in this context).
  • It offers a predictive tool to gauge potential profit success or financial losses based on production and sales strategies.
By interpreting the derivative, anyone can pinpoint how efficient or profitable increasing production might be, providing essential data for strategic planning and operational focuses.
Revenue Function
A revenue function \( R(q) \) is key in business and economics, as it models the relationship between the quantity of goods sold and the overall revenue generated. Understanding \( R(q) \) provides a detailed view of how a business earns money.

In this exercise's scenario, \( R(q) \) represents revenue generated when \( q \) billion units are sold, measured in million dollars. It serves as a mathematical depiction of a business's ability to convert sold goods into money, complicated by the scale of billions and millions in this example.

  • The function permits the calculation of expected revenue at any sales level, helping forecast and prepare for financial planning.
  • It assists in identifying revenue peak points and understand impacts of varying production levels.
  • Utilizing the revenue function in strategy allows companies to make informed choices about production quotas and pricing.
In all, the revenue function is not just a calculation tool, but a whole ensconced strategy guide essential for navigating business financial landscapes.

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Most popular questions from this chapter

Generic Profit If the marginal profit is negative for the sale of a certain number of units of a product, is the company that is marketing the item losing money on the sale? Explain.

A software developer is planning the launch of a new program. The current version of the program could be sold for 100 . Delaying the release will allow the developers to package add-ons with the program that will increase the program's utility and, consequently, its selling price by 2 for each day of delay. On the other hand, if they delay the release, they will lose market share to their competitors. The company could sell 400,000 copies now but for each day they delay release, they will sell 2,300 fewer copies. a. If \(t\) is the number of days the company delays the release, write a model for \(P\), the price charged for the product. b. If \(t\) is the number of days the company will delay the release, write a model for \(Q,\) the number of copies they will sell. c. If \(t\) is the number of days the company will delay the release, write a model for \(R\), the revenue generated from the sale of the product. d. How many days should the company delay the release to maximize revenue? What is the maximum possible revenue?

For Activities 7 through \(18,\) write the first and second derivatives of the function. \(L(t)=\frac{16}{1+2.1 e^{3.9 t}}\)

Lake Tahoe Level The level of Lake Tahoe from October \(1,1995,\) through July \(31,1996,\) can be modeled as $$ L(d)=\left(-5.345 \cdot 10^{-7}\right) d^{3}+\left(2.543 \cdot 10^{-4}\right) d^{2} $$ \(-0.0192 d+6226.192\) feet above sea level \(d\) days after September \(30,1995 .\) (Source: Based on data from the Federal Watermaster, U.S. Department of the Interior) a. According to the model, did the lake remain below the federally mandated level from October \(1,1995,\) when \(d=1,\) through July \(31,1996,\) when \(d=304 ?\) b. Calculate the location and value of any relative extrema for the lake level on the interval between \(d=1\) and \(d=304\).

A tin-container manufacturing company uses the same machine to produce different items such as popcorn tins and 30 -gallon storage drums. The machine is set up to produce a quantity of one item and then is reconfigured to produce a quantity of another item. The plant produces a run and then ships the tins out at a constant rate so that the warehouse is empty for storing the next run. Assume that the number of tins stored on average during 1 year is half of the number of tins produced in each run. A plant manager must take into account the cost to reset the machine and the cost to store inventory. Although it might otherwise make sense to produce an entire year's inventory of popcorn tins at once, the cost of storing all the tins over a year's time would be prohibitive. Suppose the company needs to produce 1.7 million popcorn tins over the course of a year. The cost to set up the machine for production is \(\$ 1300,\) and the cost to store one tin for a year is approximately 1. b. How many runs are needed during one year, and how often will the plant manager need to schedule a run of popcorn tins?

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