/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 30 Lake Tahoe Level The level of La... [FREE SOLUTION] | 91Ó°ÊÓ

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Lake Tahoe Level The level of Lake Tahoe from October \(1,1995,\) through July \(31,1996,\) can be modeled as $$ L(d)=\left(-5.345 \cdot 10^{-7}\right) d^{3}+\left(2.543 \cdot 10^{-4}\right) d^{2} $$ \(-0.0192 d+6226.192\) feet above sea level \(d\) days after September \(30,1995 .\) (Source: Based on data from the Federal Watermaster, U.S. Department of the Interior) a. According to the model, did the lake remain below the federally mandated level from October \(1,1995,\) when \(d=1,\) through July \(31,1996,\) when \(d=304 ?\) b. Calculate the location and value of any relative extrema for the lake level on the interval between \(d=1\) and \(d=304\).

Short Answer

Expert verified
Lake stayed below 6229.1 feet; relative maximum at critical point within interval.

Step by step solution

01

Interpret the Question

The problem is asking two things: whether the lake level remained below a certain level (assumed to be 6229.1 feet from context), and whether there are any points where the direction of change in the lake level reversed within the given interval.
02

Setup Polynomial Function

The function given is \( L(d) = (-5.345 \times 10^{-7})d^3 + (2.543 \times 10^{-4})d^2 - 0.0192d + 6226.192 \). This function models the lake level as a function of the days \( d \).
03

Evaluate Level at Endpoints

Calculate \( L(1) \) and \( L(304) \) to check the level at the start and end of the interval. These calculations will help evaluate whether the lake stays below a certain federally mandated level.
04

Differentiate Function

Find the derivative \( L'(d) \) to locate the critical points, which will help determine where any relative extrema (local maxima or minima) may occur. Use the power rule to find \( L'(d) \).
05

Find Critical Points

Set the derivative \( L'(d) \) equal to zero to solve for \( d \). The solutions are potential points of relative extrema within the interval \( d = 1 \) to \( d = 304 \).
06

Evaluate Function at Critical Points and Endpoints

Substitute the critical points found in Step 5 back into \( L(d) \) to find the corresponding lake levels. Compare these with values at \( d = 1 \) and \( d = 304 \) to determine the relative extrema.
07

Conclusion

Compare the lake levels calculated at all tested points (endpoints and critical points) against the federally mandated level. Summarize whether the lake level stayed below this threshold and identify any relative extrema based on function values.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polynomial Functions
Polynomial functions are expressions built from variables and constants using addition, subtraction, multiplication, and non-negative integer exponentiation of variables. In the exercise about Lake Tahoe, the level of the lake is represented by a polynomial function of degree 3:
\[L(d) = (-5.345 \times 10^{-7})d^3 + (2.543 \times 10^{-4})d^2 - 0.0192d + 6226.192\]This equation is made up of several terms:
  • A cubic term \((-5.345 \times 10^{-7})d^3\), which indicates the function is a cubic polynomial with a leading coefficient of \(-5.345 \times 10^{-7}\).
  • A quadratic term \((2.543 \times 10^{-4})d^2\) that adds curvature to the graph.
  • A linear term \(-0.0192d\), contributing to the slope of the function.
  • A constant term \((6226.192)\) representing the lake level when \(d = 0\).
Polynomial functions like this can model complex phenomena, such as lake levels, over a period of time.
Derivative
The derivative of a function reflects how the function's output value changes as its input changes. In calculus, finding the derivative is a crucial step in analyzing the behavior of polynomial functions like the one modeling Lake Tahoe.
For the function \(L(d)\), we use the power rule to calculate its derivative \(L'(d)\):
\[L'(d) = \frac{d}{dd}(-5.345 \times 10^{-7})d^3 + \frac{d}{dd}(2.543 \times 10^{-4})d^2 - \frac{d}{dd}0.0192d\]Using the power rule \((nx^{n-1})\), the derivative becomes:
  • \(L'(d) = -1.6035 \times 10^{-6}d^2 + 5.086 \times 10^{-4}d - 0.0192\)
Finding the derivative enables us to locate critical points, helping determine where the lake level changes its behavior.
Critical Points
Critical points occur where the derivative of a function is zero or undefined. These are the points where the function's graph may change direction, indicating potential maxima, minima, or points of inflection.
In our exercise, we need to find the critical points of the lake level function \(L(d)\) by setting its derivative \(L'(d)\) to zero:
\[ -1.6035 \times 10^{-6}d^2 + 5.086 \times 10^{-4}d - 0.0192 = 0 \]Solving this quadratic equation will provide the values of \(d\) where the lake level might have relative extrema (maximum or minimum points).By identifying these critical points, we can investigate their corresponding lake levels and determine how the lake behaved between the given times.
Relative Extrema
Relative extrema are the highest or lowest points in a specific section of a function's graph, specifically known as local maxima and minima. When examining the lake level, we calculate the values of \(L(d)\) at the critical points and endpoints of the interval.
The comparison will help identify where the lake level reaches local highs and lows between \(d = 1\) and \(d = 304\).
  • A relative maximum occurs where \(L(d)\) is higher than at neighboring points.
  • A relative minimum is where \(L(d)\) is lower than nearby points.
To decide if these are maxima or minima, we compare their corresponding lake levels. This helps us describe the behavior of Lake Tahoe's water level over the specified timeframe and assess whether it fell below the federally mandated limit.

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