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Show that the curvature of the function of y=1−x2,x∈(−1,1), is constant, but its second derivative varies with x.

Short Answer

Expert verified

The value of the second derivative depends on x.

The curvature of the function is 1 which is constant.

Step by step solution

01

Step 1. Given information.

We have to show that the curvature of the function of y=1−x2,x∈(−1,1), is constant, but its second derivative varies with x.

02

Step 2. To show that the second derivative varies with x 

if y=f(x) is a twice-differentiable function then the curvature of f is given by

k=f′â¶Ä²(x)1+f′(x)232

Since,

y=f(x)=1−x2f′(x)=121−x2(−2x)⇒f′(x)=−x1−x2

Use the quotient rule to find f′â¶Ä²(x):

f′â¶Ä²(x)=1−x2(−1)+x121−x2(−2x)1−x2f′â¶Ä²(x)=−1−x2−x21−x232f′â¶Ä²(x)=−11−x232

The value of the second derivative depends on x.

03

Step 3. To show that the curvature of the function is constant

Substituting f′andf′â¶Ä²values in the formula for k we get :

k=−11−x2321+−x1−x2232k=1−x2321+x21−x232=−11−x2321−x2+x21−x232k=11−x232⋅1−x2321k=1

The curvature of the function is 1 which is constant.

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