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Explain why the series is not a power series in x-x0.Then use the ratio test for absolute convergence to find the values of xfor which the given series converge ∑k=0∞-1k1k!x-k

Short Answer

Expert verified

The value of xfor which the seriesrole="math" localid="1649519156951" ∑k=0∞-1k1k!x-k converges whenx∈R.

Step by step solution

01

Step 1. Given information. 

The given power series is∑k=0∞-1k1k!x-k.

02

Step 2. Find the values of x for which the given series converge. 

Since, the power of the xis negative. So the series is not power series.

Now, the value of bkis

bk=-1k1k!x-kand bk+1=-1k+11k+1!x-k+1

Thus,

limk→∞bk+1bk=limk→∞-1k+11k+1!x-k+1-1k1k!x-k=limk→∞-1xk+1

So, for k→∞the value of limit will always be zero.

Therefore the value of xfor which the series ∑k=0∞-1k1k!x-kconverges whenx∈R.

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