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91Ó°ÊÓ

In exercises 59-62 concern the binomial series to find the maclaurin series for the given function .

1(1+x)2

Short Answer

Expert verified

The maclaurin series for the given function is

(1+x)−2=1−2x+3x2−4x3+⋯

Step by step solution

01

Step 1. Given information 

We have been given

f(x)=1(1+x)2

to find the maclaurin series by using binomial series

02

Step 2.Defining the series 

For any non- zero constant p, the Maclaurin series for the function g(x)=(1+x)pis called the binomial series which is given by ∑k=0∞ pkxk where the binomial coefficient is

pk=p(p−1)(p−2)⋯(p−k+1)k!ifk>01,ifk=0

03

Step 3. Binomial series for the given function is 

So for the function f(x)=1(1+x)2, the binomial series is

(1+x)−2=∑k=0∞ −2kxk

implies that ,

(1+x)−2=−20x0+−21x1+−22x2+−23x3+⋯=1−2x+−2(−3)2!x2+−2(−3)(−4)3!x3+⋯=1−2x+3x2−4x3+⋯
04

Step 4. The maclaurin series for given function is 

The maclaurin series of given function f(x)=1(1+x)2is

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