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91Ó°ÊÓ

Find the Maclaurin series for the functions in Exercises 51–60

by substituting into a known Maclaurin series. Also, give the

interval of convergence for the series.

xcos(x2)

Short Answer

Expert verified

The answer isxcos(x2)=x∑k=0∞(-1)k(2k)!x4k+1

Step by step solution

01

Step 1. Given Information

Consider the functionxcos(x2)

02

Step 2 

We know that the Maclaurin series for the function g(x)=cos(x)is cosx=∑k=0∞(-1)k(2k)!x2k

So, to find the Maclaurin series for the function f(x)=xcos(x2), we replace xby x2and then multiply by cosx

Therefore,xcos(x2)=x∑k=0∞(-1)k(2k)!(x2)2k =x∑k=0∞(-1)k(2k)!x4kimplies that,role="math" localid="1649865748409" xcos(x2)=x∑k=0∞(-1)k(2k)!x4k+1

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