/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 36 Gradients: Find the gradient of ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Gradients: Find the gradient of the given function, and find the direction in which the function increases most rapidly at the specified point P.

f(x, y ,z) = ln(x + y + z), P = (e, 0, −1) .

Short Answer

Expert verified

Thegradientis∇f(x,y,z)=1x+y+z,1x+y+z,1x+y+zandthedirectioninwhichincreasesmostrapidlyatp=(e,0,-1)is∇f(e,0,-1)=1e-1,1e-1,1e-1

Step by step solution

01

Step 1. Given 

f(x, y ,z) = ln(x + y + z)

02

Step 2.  Finding gradient of f(x, y ,z) = ln(x + y + z)

Thegradientofafunctionf(x,y,z)isdefinedby∇f(x,y,z)=∂f∂xi+∂f∂yj+∂f∂zk.here,f(x,y,z)=ln(x+y+z).So,itsgradientisgivenby,∇f(x,y,z)=∂(ln(x+y+z))∂xi+∂(ln(x+y+z))∂yj+∂(ln(x+y+z))∂zk=1x+y+zi+1x+y+zj+1x+y+zk.Hence,thegradientis∇f(x,y,z)=1x+y+z,1x+y+z,1x+y+z.

03

Step 3. Finding points in the direction in which f increases .

Asthegradientofafunctionatapointp,pointsinthedirectioninwhichfincreasesmostrapidlyHerep=(e,0,-1),so∇f(e,0,-1)=1e-1i+1e-1j+1e-1kHencethedirectioninwhichincreasesmostrapidlyatp=(e,0,-1)is∇f(e,0,-1)=1e-1,1e-1,1e-1

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.