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91Ó°ÊÓ

In exercise 35-38, find the directional derivative of the given function at the specified point Pand in the direction of the given vector v.

role="math" localid="1650433937626" f(x,y)=xy2atP=(9,−3),v=2i+7j

Short Answer

Expert verified

The directional derivative of the function is∇f(P).u=44953.

Step by step solution

01

Directional derivation.

For a given function P=(x0,y0)=(9,-3)and v=2i+7j, we must find the directional derivative f(x,y)=xy2.

role="math" localid="1650434437663" v=22+72=53

∴u=(α,β)=253,753

02

Directional unit vector.

The directional derivative of a variable at point Pwith directional unit vector u is calculated as follows:

localid="1650642364216" ∇f(P)⋅u=∇f(9,−3)×u=dfdx(9,−3)i+dfdy(9,−3)j×253i+753j

localid="1650642387307" =1y2(9,−3)i+−2xy3(9,−3)j×253i+753j

localid="1650642404428" =19i+1827j×253i+753j

=1.29.53+18.727.53

localid="1650642421175" =29.53+12627.53

=29.531+633

∇f(P).u=44953

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