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91Ó°ÊÓ

Let S=x,y|x2+y2≤1,x≥0

Find the centroid of S.

Short Answer

Expert verified

Answer is43Ï€,0

Step by step solution

01

Step 1. Given information

S=x,y|x2+y2≤1,x≥0

02

Step 2. Explanation

S=x,y|x2+y2≤1,x≥0

x¯=∫01∫-1-x21-x2xdydx∫01∫-1-x21-x2dydxx¯=∫01x[y]-1-x21-x2dx∫01[y]-1-x21-x2dx=2∫01x1-x2dx2∫011-x2dx=∫01x1-x2∫011-x2dx=-131-x23/20112x1-x2+sin-1x01=13π4=43π

y¯=∫01∫-1-x21-x2ydydx∫01∫-1-x21-x2dydx=∫01y22-1-x21-x2dx∫01[y]-1-x21-x2dx=∫01[0]dx∫01[0]dx=0

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