/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q 52. Find the volume of solid of regi... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the volume of solid of region bounded above by the sphere with equation ÒÏ=2and bounded below by the cone with equationÏ•=Ï€3.

Short Answer

Expert verified

The required volume isV=83Ï€units.

Step by step solution

01

Given Information

The given equations are ÒÏ=2andÏ•=Ï€3.

02

Evaluation of limits

We know that

x=ÒÏsinÏ•cosθ,y=ÒÏsinÏ•sinθ,z=ÒÏcosÏ•

and

ÒÏ=x2+y2+z2,tanθ=yx,cosÏ•=zÒÏ,dxdydz=ÒÏ2sinÏ•dÒÏdÏ•dθ

Limits of spherical coordinates are

0<θ<2Ï€,0<Ï•<Ï€3,0<ÒÏ<2

To find the volume as per given conditions, we will use spherical coordinates.

03

Calculation of Volume

Required Volume is V=∭Vdxdydz

V=∫ϕ=0Ï€/3∫ÒÏ=02∫θ=02Ï€ÒÏ2sinÏ•dÒÏdÏ•dθ

V=∫ϕ=0Ï€/3sinÏ•dϕ∫ÒÏ=02ÒÏ2dÒÏ∫θ=02Ï€dθ

V=(-cosÏ•)0Ï€/3ÒÏ33ÒÏ=0ÒÏ=2θθ=02Ï€

Application of limits yields

V=1-12233{2Ï€}

Hence, V=83Ï€units

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.