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Evaluate each of the double integrals in Exercises 37-54as iterated integrals.

∫∫Rex+ydA,

whereR=x,y|0≤x≤1and0≤y≤1.

Short Answer

Expert verified

The value of double integral is :-

∫∫Rex+ydA=e-12

where,R=x,y|0≤x≤1and0≤y≤1

Step by step solution

01

Step 1. Given Information 

We have given the following double integral :-

∫∫Rex+ydA,

where R=x,y|0≤x≤1and0≤y≤1.

We have to evaluate this double integral.

02

Step 2. Use iterated integrals

The given double integral is :-

∫∫Rex+ydA,

where R=x,y|0≤x≤1and0≤y≤1.

Then by using Fubini's Theorem, we can writ this double integral as following :-

role="math" localid="1650413616232" ∫∫Rex+ydA=∫01∫01ex+ydxdy

We can write this as following :-

∫01∫01ex+ydxdy=∫01∫01exeydxdy

Then by using iterated integrals, we have :-

role="math" localid="1650413690814" ∫01∫01exeydxdy=∫01∫01exeydxdy

Now we can solve this integral as following :-

∫01∫01exeydxdy=∫01eyex10dy=∫01eye1-e0dy=∫01eye-1dy=e-1ey10=e-1e1-e0=e-1e-1=e-12

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