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Let be a lamina in the xy-plane. Suppose is composed of n non-overlapping lamin忙 role="math" localid="1650321722341" 1,2,,n.Show that if the masses of these lamin忙 are m1,m2,,mnand the centers of masses are x1,y1,x2,y2,,xn,yn,then the center of mass of is x,y,where

x=k=1nmkxkk=1nmkandy=k=1nmkykk=1nmk.

Short Answer

Expert verified

center of mass x&yis the ratio of the sum of all linear moments of the mass about they-axis and x-axis respectively to the sum of all masses.

So the center of mass of isx=k=1nmkxkk=1nmkandy=k=1nmkykk=1nmk.

Step by step solution

01

Step 1. Given information.    

luminacomposed ofn non-overlapping lamin忙 1,2,,n.

masses of lumina role="math" localid="1650321740246" 1,2,,nare m1,m2,,mnwith a center of masses at x1,y1,x2,y2,,xn,yn.

center of mass ofisx=k=1nmkxkk=1nmkandy=k=1nmkykk=1nmk.

02

Step 2. moment of the mass. 

The x-coordinate of the center xof mass of 1is role="math" localid="1650322246084" x=Mym1

So linear moment of the mass about the y-axis of 1is My=m1x

similarly, a linear moment of the mass about the y-axis of 2,3,,nare following.

My=m2xMy=m3xMy=mnx

The y-coordinate of the center of mass yof 2is y=Mym2

So linear moment of the mass about the x-axis of 1is Mx=m1y

similarly, a linear moment of the mass about the x-axis of 2,3,,nare following.

Mx=m2yMx=m3yMx=mny

03

Step 3. Center of mass. 

center of mass xis the ratio of the sum of all linear moments of the mass about the y-axis to the sum of all masses.

role="math" localid="1650322903342" x=m1x1+m2x2++mnxnm1+m2++mnx=k=1nmkxkk=1nmk

center of mass yis the ratio of the sum of all linear moments of the mass about the x-axis to the sum of all masses.

role="math" localid="1650322895845" y=m1y1+m2y2++mnynm1+m2++mny=k=1nmkykk=1nmk

So the center of mass of isx=k=1nmkxkk=1nmkandy=k=1nmkykk=1nmk.

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