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91Ó°ÊÓ

Evaluate the iterated integral :

∫13 ∫−15 ∫03 xy2zdzdydx

Short Answer

Expert verified

1892

Step by step solution

01

Step 1. Given information.

Given integral is :

∫13 ∫−15 ∫03 xy2zdzdydx

We have to evaluate it.

02

Step 2. Evaluate.

Given ∫13 ∫−15 ∫03 xy2zdzdydx

=∫13 ∫−15 ∫03 xy2zdzdydx=∫13 ∫−15 xy2∫03 zdzdydx=∫13 ∫−15 xy2z2203dydx=∫13 ∫−15 xy292dydx

03

Step 3. Integrate with respect to y.

=∫13 92x∫−15 y2dydx=∫13 92xy33−15dx=∫13 92x533−(−1)33dx=∫13 92x(42)dx=∫12 189xdx

Integrate with respect to x.

=189∫01 xdx=189x2201=18912−0=1892

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