/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 54 You may have noticed that even v... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

You may have noticed that even very simple functions give rise to arc length integrals that we have no idea how to compute. Use a graphing calculator to approximate a definite integral that represents the arc length of the given function f(x) on the interval [a, b].

f(x)=x2+1,a,b=0,4

Short Answer

Expert verified

The approximate value is16.819.

Step by step solution

01

Step 1. Given information. 

Consider the function isfx=x2+1,a,b=0,4.

02

Step 2. Use arc length formula.

The formula for a function to find the arc length from x=ato x=bis given by ∫ab1+f'x2dx.

03

Step 3. Find definite integral for the given function.

Substitute corresponding values into the arc length formula.

∫ab1+f'x2dx=∫041+ddxx2+12dx=∫041+2x+02dx=∫041+4x2dx

04

Step 4. Use graphing calculator.

Find the approximate value of definite integral ∫041+4x2dxwith the help of graphing calculator.

∫041+4x2dx≈16.819

The area under the definite integral between the interval 0,4in the graphing calculator is represented as follows.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.